
How do you use logarithmic differentiation to find the derivative of
Mar 17, 2018 · (dy)/(dx)=(cosx)^x[lncosx-xtanx] y=(cosx)^x take natural logs of bothe sides lny=ln(cosx)^x =>lny=xlncosx ...
How do you graph y=-cosx-1? - Socratic
Oct 27, 2016 · graph{-cosx -1 [-5, 5, -2.5, 2.5]} It is important to learn what the graphs of y=sinx and y=cosx look like; The graph of y=cosx is as follows; graph{cosx [-5, 5, -2.5, 2.5]} So, the …
What is the range of the function y = cos x? | Socratic
Sep 24, 2014 · The range of a function is all possible output, or y, values. The range of y=cos x is from -1 to 1. In interval notation, the range is [-1,1] * Note that square brackets [ ] are used …
Is the trig function: even, odd, neither y=cosx? | Socratic
Oct 13, 2015 · Is the trig function: even, odd, neither #y=cosx#? Trigonometry Graphing Trigonometric Functions General Sinusoidal Graphs. 1 Answer
Minimum vertical distance between graph of y=2+sinx and y=cosx …
Jul 30, 2018 · Minimum vertical distance between graph of #y=2+sinx and y=cosx# is ? Precalculus. 1 Answer P dilip_k ...
What is the smallest value of y=cos x? - Socratic
Apr 15, 2018 · -1 We know that "the Domain of cosine" is RR ,but "the Range of cosine" is [-1,1] i.e. -1 <= cosx <= 1 It is clear that ,the smallest value of y=cosx is: -1
How do you translate the graph of #y=cosx+3#? - Socratic
Aug 20, 2017 · You have to translate a graph of y=cosx 3 units up. See explanation. The general rule of translating graphs of functions is: To get a graph of a function: f(x-a)+b from the graph …
If y = cosx^3sin^2(x^5), what is dy/dx? - Socratic
Nov 19, 2017 · See explanation According to the product rule, d/dx[f(x)*g(x)]=f(x)*g'(x)+g(x)*f'(x), where f(x) = cos(x^3) and g(x) = sin^2 (x^5) Therefore (be careful with the chain rule), d/dx …
How do you find the equation of the line tangent to y=cosx
Jul 30, 2017 · How do you find the equation of the line tangent to #y=cosx-sinx#, at (pi,-1)?
How do you graph y=sin x and y=cos x? - Socratic
Nov 9, 2014 · Here are the graphs: y=sinx y=cosx I hope that this was helpful.