May 2, 2017 · Coming from a C++ background I have expected this to work. However, it fails to compile with "Cannot implicitly convert type 'T' to string" and "Cannot convert type 'T' to string" …

Apr 3, 2018 · Meaning Array<T> is the interface (for lack of a better word) and when we create a concrete type we replace T with a declared type: Array<number> So for the interface Array<T> …

Aug 9, 2010 · Now you can retrieve the type of T at runtime: Type mySuperclass = myFoo.getClass().getGenericSuperclass(); Type tType = …

public class Foo { public void Bar<T>() { var baz = new List<T>(); // get type of T } } I would like to know what type of objects the list of my class contains. So what type of T does the list property …

Jan 5, 2017 · to check if the type if nullable, you'd use typeof(T).IsGenericType, and if it is, you'd use the following to get the Name or FUllName …

Jun 29, 2016 · You have to declare T as new(), so it has to have a parameterless constructor. Then you can simply create an instance and return it: public T GetService<T>(ServiceType …

Jun 9, 2009 · Type intType = typeof(Int32); object value1 = 1000.1; // Variable value2 is now an int with a value of 1000, the compiler // knows the exact type, it is safe to use and you will have …

Type T should not be IConvertible, but Type of base.Value should. – chapluck. Commented Sep 15, 2015 at ...

Feb 11, 2015 · Why? Because under the hood, the compiler will go away and create a new type (sometimes called a closed generic type) for each different usage of the "open" generic type. …

Nov 6, 2012 · The compiler has no way to know that T, which is currently constraint to Base is actually Concrete, and that even if you test it before. So: Type type = typeof(Bar<>); Type …