How do you find the derivative of #y = tanh^-1 (1/x)#? - Socratic
Nov 2, 2016 · dy/dx=1/(1-x^2) y=tanh^-1(1/x) => tanhy=1/x Differentiating implicitly gives: (1-tanh^2y)dy/dx=-1/x^2 :. (1-(1/x)^2)dy/dx=-1/x^2 :. dy/dx=-1/((x^2)(1-(1/x)^2)) :. dy ...
How do you find the derivative of #tanh(1+e^(2x))#? - Socratic
Apr 16, 2015 · Applying chain rule, the derivative would be 2e^(2x) sech^2 (1+e^(2x))
Prove that the function f(x)=tanh^-1(x) is an odd function - Socratic
Apr 19, 2018 · The argument below can be adapted to prove that the inverse of any odd invertible function is odd. The function tanh(x) equiv (e^x-e^-x)/(e^x+e^-x) is obviously an odd function. …
Find derivation of tanh^-1x, hence differentiate y= tanh^-1 ( (2x)/ …
Jul 13, 2018 · Find derivation of #tanh^-1x#, hence differentiate #y= tanh^-1 ((2x)/(1+x^2))# ? Calculus. 1 Answer
Find derivatives y=tanh sqrt 1+t^2 - Socratic
Jun 2, 2018 · 2192 views around the world You can reuse this answer ...
Use first principles to find the gradient of #y=tanh(x)#? - Socratic
May 24, 2018 · Given #y=f(x)#, #f'(x)=lim_(hto0)(f(x+h)-f(x))/h#. #f'(x)=lim_(hto0)(tanh(x+h)-tan(x))/h# #f'(x)=lim_(hto0)((tanh(x)+tanh(h))/(1+tanh(x)tanh(h))-tan(x))/h#
What is the domain and range of #cos^-1(tanh x)#? - Socratic
May 17, 2017 · The domain is x in RR the range is y in RR: 0 < y < pi The domain of the tanh(x) function is any real number: x in RR The range of the tanh(x) function is y in RR: -1 < y < 1; …
Prove that #tanh(x/2)=sinhx/(coshx+1)#? - Socratic
Sep 27, 2017 · As #tanh(x/2)=sqrt((coshx-1)/(coshx+1))# = #sqrt(((coshx-1)(coshx+1))/((coshx+1)(coshx+1))# = #sqrt(cosh^2x-1)/(coshx+1)#
Evaluate the integral? int ln tanh(x/2)/cosh^2x dx - Socratic
Jul 24, 2017 · I got = tanh(x)ln(tanh(x/2)) - 2arctan(tanh(x/2)) + C, " "x > 0 DISCLAIMER: VERY LONG ANSWER! Well, I don't work with hyperbolics much, but I do know that: the derivative of …
How do you verify tanh x/(cosh x - sinh x tanh x) = sinh x? - Socratic
May 5, 2016 · How do you prove #(1-\cos^2 x)(1+\cot^2 x) = 1#? How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#?