May 27, 2016 · Let #sin^-1x=theta# hence #x=sintheta#. For #0<x<1# we draw a right triangle with hypotenuse equal to 1 and the other side equals to #x# like the one in the Figure below.

Jan 21, 2018 · We know that #tan^-1(1) = pi/4 approx 0.785#. tangent is an increasing function and is continuous on the interval # -pi/2 < x < pi/2#. Since tangent is increasing on that interval and #pi/4 < 1# we know that #tan(pi/4) < tan(1)#. Since #tan(pi/4) = 1# we know that #tan(1) > 1#.

Apr 19, 2015 · How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute #sin^-1 (-sqrt(3)/2)#?

Mar 17, 2018 · Let #x=tantheta=>theta=tan^-1x#. #tan^1(x+sqrt(1+x^2))# #=tan^1(tantheta+sqrt(1+tan^2theta))# #=tan^1(tantheta+sqrt(sec^2theta))#

Jul 2, 2016 · How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute #sin^-1 (-sqrt(3)/2)#?

Apr 19, 2016 · Let #a =tan^(-1)(2/3)#. As tan a = 2/3, cos a and sin a should both have the same sign and #a = tan^(-1)(2/3)=33.7^o or 213.7^o#, in #[0, 2pi]#.

Aug 31, 2016 · 11pi/6 say x = tan^-1 tan(11pi/6) so, tan x = tan(11pi/6) or, x = 11pi/6

The inverse tangent function will return a negative angle for this where #cos(theta) = -sin(theta)#. The angle that it returned is: The angle that it returned is: #theta = -pi/4#

Jul 18, 2018 · What is the derivative of #(tan^-1 (x+2)/(1+2x))#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer

Jan 8, 2017 · The inverse tangent function cancels the tangent function: tan^-1(tan((2pi)/3)) = (2pi)/3