Jul 25, 2016 · I changed it to cos: I know that sec (0)=1/cos (0) and that cos (0)=1 so: sec (0)=1

Oct 17, 2015 · 0 is a special angle. cot, csc, and sec are actually just the reciprocals of tan, sin, and cos respectively. Solving cot 0: cot0 = 1 tan0 = 1 0 this is undefined Solving csc 0: csc0 = 1 sin0 = 1 0 this is undefined Solving sec 0: sec0 = 1 cos0 = 1 1 = 1

Mar 17, 2016 · sec (-pi/6)=sec (pi/6)=2/sqrt3 sec (-theta)=sectheta

Feb 5, 2016 · That improper integral diverges (does not exist). Because secx is not defined at pi/2 which is less than 2, the integral is improper. Improper integral are probably not suitable for an "Introduction to Integration". In the early portion of a course on integration, the definite integral is often defined for function defined on some closed interval [a,b]. If this is the only definition you …

Jun 2, 2015 · Call sec x = t. Use the trig identity: 1 + tan^2 x = sec^2 x = t^2 f (x) = 2 (t^2 - 1) - 3t + 3 = 2t^2 - 3t + 1 = 0 Since (a + b + c ) = 0, one real root is t = 1 and the other is t = c/a = 1/2 Solve the 2 basic trig equations: t = 1 and t = 1/2. a. t = sec x = 1/cos x = 1 --> cos x = 1 -> x = 2pi b. t = sec x = 1/cos x = 1/2 -> cos x = 2 (rejected) Check: x = 2pi -> cos x = 1 -> sec = t = 1 ...

Nov 16, 2017 · I got f' (0) = 0 We have: f (x) = 1/cosx = (cosx)^-1 By the chain rule, letting y = u^-1 and u = cosx, then y' = -1/u^2 and u' = -sinx. f' (x) = -1/u^2 * -sinx = -1/cos^2x * -sinx = tanxsecx We simplify evaluate x= 0 within the derivative. f' (0) = tan (0)sec (0) = 0 Hopefully this helps!

Nov 20, 2017 · How do you find all solutions of the equations sec2 x − sec x = 2 in the interval [0, 2π)?

Mar 17, 2018 · sec(2π) can be written as sec(0) because sec(2π) = sec(2π− 0) = sec(0) and sec(0) = 1 So sec(2π) = 1

May 3, 2018 · Suppose tan (θ) is undefined and sin (θ) < 0. Find the exact values of the 6 trigonometric functions of the angle θ?

Nov 2, 2015 · Given secθ=6/5 and tanθ<0, how do you find the values of the other five trigonometric functions?