Sep 4, 2023 · Indeed, but if I directly convert 1672 MeV/c^2 using the fundamental charge: (1672 * 10^6 eV/c^2) * 1.609 J/eV, I get 2.68 * 10^-10 J/c^2. This is kilograms. Same wrong answer. I'm missing something here. I have to divide again by c^2 and I have no idea why.

Jun 21, 2006 · To go from MeV to J you multiply by 1.6E-13. To go the other way you just divide by that same number. Of course that's very specific. In general, it's more practical to simply remember the definition of the electron volt as 1.6E-19 J and go from there.

Oct 9, 2010 · The electron-volt, eV, is a unit of energy (1 eV = 1.602 10^-19 J, 1 MeV = 1.602 x 10^-13 J). Since the unit of momentum is an energy unit divided by a velocity unit, nuclear physicists usually specify momenta of nuclei in units of MeV/c, where c is the speed of light (c = 2.998 108 m/s).

Sep 16, 2009 · The speed is expressed as a fraction of c, the speed of light, which acts as a "speed limit" for all massive particles. If an electron at rest (which already has some energy due to its mass) were to be given an additional 1 MeV of kinetic energy, it …

Apr 8, 2003 · Yeah -- lots of times in particle physics we want to work in "natural" units where mass, momentum, and energy all the same units. Then you will see momentum expressed in units of "eV/c" and mass in units of "eV/c^2" (or MeV etc as the case may be.) eg 34 MeV/c^2 ~ 2e-13 J/c^2 ~ 2e-30 kg

May 20, 2013 · I can shoot 200 MeV of energy into many things over a period of time without causing even the slightest damage. One 200 MeV electron hitting a beam pipe of an accelerator doesn't cause significant damage.

Nov 26, 2011 · Homework Statement How do I find the binding energy for the nuclei of Lithium 6. N=Z=3, atomic mass=6.015 u, binding energy per nucleon= 5.33 MeV The...

May 1, 2015 · hey guys i have this question which says: On average the fission of a uranium 235 nucleus releases 200 MeV of energy. How many joules of energy will be released by the fission all the uranium 235 atoms in our fuel. my answer: (200*10^6)*1.6*10^-19 which is …

Aug 28, 2023 · H = - 2J 1 ∑ S i S j - 2J 2 ∑ S i S k - D ∑ S i2, where J 1 is the exchange constant between two spins of the same basal plane (0.83 meV), J 2 is the exchange constant between two different basal planes (- 0.58 meV), D is the anisotropic constant (0.165 meV) and the experimental T N = 139.5 K. This compound is an A-type Néel antiferromagnetic. Below, I …

Sep 30, 2010 · A point source of Co-60 gamma rays emits equal numbers of photons of 1.17 and 1.33 MeV, giving a flux density of 5.7 x 10^9 photons/cm^2-sec at a specified location. a.)What is the energy flux density there, expressed in J/m^2-min? b.)What is the energy fluence of 1.17 MeV photons during 24 hours in J/m^2? My work: