Nov 5, 2019 · In this particular example, only option b satisfy the definition of the % m/v quantity we are expressing since only b lists volume of KI solution. Let's check the math. Let's check the math. Since $\pu{575.0 mg} = \pu{0.5750 g},$ there is $\pu{0.5750 g}$ $\ce{KI}$ per $\pu{10.00 mL}$ of $\ce{KI}$ solution, and normalizing to $\pu{100 mL}$ we ...

Apr 16, 2019 · $\begingroup$ You seem to be saying the textbook's answer is flawed because you can't compare Cp and Cv, the reason being that the difference in constraints implicit to Cp vs. Cv brings you to different final states (making it apples to oranges).

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May 20, 2024 · I tried to calculate the point where the rate of change of temperature wrt volume would become 0 but my answer didn't match. The solution given was: Process will turn from endothermic to exothermic at point where slope of P-V graph satisfy the slope of adiabatic curve for same gas. I couldn't understand why this is true. Could anyone please ...

May 2, 2022 · The $\ce{E^°(M^3+/M^2+)}$ standard electrode potential for $\ce{V}$ has a low negative (that is, a relatively more positive) value. This is attributed to the greater stability of $\ce{V^2+}$ as given in the text. This can be seen in the $\ce{E^°(M^3+/M^2+)}$ values for $\ce{Ti,V,Cr}$ being $\pu{-0.37, -0.26, -0.41}$ respectively.

Jun 27, 2017 · moderate (or medium) w eak Notations such as m-w and w-s presumably indicate a peak intensity that is variable in the indicated range, depending on the properties of the particular molecule of interest.

May 6, 2015 · I know I should divide $\pu{g L-1}$ by the molar mass of the substance, but I don't seem to find the specific answer on Google.

May 12, 2019 · M (minus, or Λ) is a left-handed helix in axial chirality. Small caps $\mathrm{\small M}$ is used for concentration (amount-of-substance concentration) of substance. It's rarely mentioned that when "M" is used in place of mol/L, it's supposed to be small caps "M" ($\mathrm{\small M}$), not just capital "M

Jan 27, 2021 · $$ pV = nRT = \frac{m}{M}RT $$ you can express the density $\rho = \frac m V$ in terms of molar mass, pressure, ideal gas constant, and temperature: $$ \rho = \frac{pM}{RT} $$ With the units you use in your second example, this yields a density in $\mathrm{g\,m^{-3}}$, whereas you insert a density in $\mathrm{kg\,m^{-3}}$ into your first ...

Feb 28, 2017 · The mistake that you have made is incorrect understanding of M. From what I remember, M was number of single bonds, which would be only with a monovalent atom, in the context you learnt tbe formula. This was taught in chemical bonding where only atoms are bonded to central atom.