
Proof that trace of 'hat' matrix in linear regression is rank of X
The hat matrix is a projection matrix so it's idempotent. i.e. it only has eigenvalues of 0 or 1.
statistics - In linear regression, why is the hat matrix idempotent ...
Dec 24, 2017 · I believe you’re asking for the intuition behind those three properties of the hat matrix, so I’ll try to rely on intuition alone and use as little math and higher level linear algebra concepts as possible. Preliminaries
regression - Decomposing Hat Matrix into Orthogonal Parts
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linear algebra - Hat matrix multiplied by matrix of constants ...
Sep 28, 2020 · The matrix $\bf{H}$ is the projection matrix onto the column space of $\bf{X}$. But the first column of $\bf{X}$ is all ones; denote it by $\bf{u}$ . This implies that $\bf{Hu}$ = $\bf{u}$ , because a projection matrix is idempotent.
Hat matrix with simple linear regression - Mathematics Stack …
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Hat Matrix Identities in Regression - Mathematics Stack Exchange
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Relation between trace and rank for projection matrices
Oct 22, 2014 · If we now pass to the Jordan Normal Form $\;J_A\;$ of $\;A\;$ (i.e., in this case the diagonal form of the matrix) , we see that we'll get as many $\;1$ 's on the diagonal as the rank of the matrix, because $\operatorname{rank} J_A = \operatorname{rank} A$, and thus we have that $$\operatorname{Tr} A= \operatorname{Tr} J_A= \operatorname{rank} A$$
linear algebra - Multiplication of Projection/Hat matrix and …
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matrices - How to prove that non-diagonal elements of hat matrix …
Oct 26, 2015 · Proof that trace of 'hat' matrix in linear regression is rank of X. 2.
Why is the sum of elements in each row of $X(X^T X)^{-1} X^T$ in …
Oct 27, 2018 · Properties of OLS hat matrix from a design matrix whose rows sum to $1$ 0.