Jun 15, 2014 · Why is [Cu(h2o)6]2+ blue and [CuCl4]2-yellow? From what I understand, H2O is a stronger ligand than Cl-. Stronger ligands split the d-orbitals in the complex ion to a greater extent than a weak ligand does…As a result the colour absorbed is towards the high energy (violet) end of the spectrum.

Yes, I was in a rush so didnt really complete the answer but you're right. However, having gone through the past papers though you don't need to go into anywhere near the detail the textbook goes into. 3 marks seem to be awarded for d-orbitals split; electron promoted from lower energy level to higher energy level; light from visible region is absorbed Seems pretty fair/generous.

Jun 1, 2022 · Your equation starts half-way through the process of adding NH3 to [Cu(H2O)6]2+, so would not be accepted as the Q would say something like show the equation for the addition of NH3 to [Cu(H2O)6]2+ and you showed and equation for the addition of NH3 to [Cu(H2O)4(OH)2] In a related issue, you're probably confused why the addition of NH3 to [Cu ...

Apr 28, 2023 · There are some transition metal ions for which NH3 does fully replace H2O ligands (e.g Cr^3+, Co^2+ to name a few). In the case of copper, there are some complications discussed beyond A level that explain why only 4 of the 6 water ligands are replaced. You are not expected to understand these, but you are expected to know that this particular ...

Nov 4, 2020 · Write an equation for the reaction between [Cu(H2O)6]2+ and EDTA4– ions. Calculate the volume of the EDTA4– solution needed to react with a 25.0 cm3 sample of the water. Justify whether this titration will give an accurate value for the concentration of …

May 16, 2021 · please can someone identify what topic this is in AQA chemistry Solution A contains the compound [Cu(H2O)6]Cl2 State the type of bonding between the oxygen and hydrogen in this compound. [1 mark] State why the chloride ions in this compound are not considered to be ligands.

Cu2+ + NH3---> [Cu(NH3)4]2+ It says in the AQA spec that: "know that transition metals ions commonly form octahedral complexes with small ligands eg. H2O and NH3" Therefore, ut should be 6, not 4, right?

Feb 26, 2022 · Write an equation for the reaction, in aqueous solution, between [Cu(H2O)6]2+ and an excess of chloride ions. The answer is [Cu(H2O)6]2+ + 4Cl– → [CuCl4]2– + 6H2O It seems very straightforward but I don't understand why you don't use 6Cl-to displace all the H20?

May 9, 2024 · Is this q based off of the process of elimination or smth*on*the*spec Im assuming its true that the Cu2+ is in its aqua ion form and is actually [Cu(h20)6]2+. i thought it would react with the cl-from the hcl and entropy and stuff makes the ligand substitution feasible turning it into [Cu(cl)4]2-. But i searched it up and it's just displacement ...

Apr 18, 2024 · Are you thinking of copper(II), as in [Cu(H2O)6]^2+ + 2NH3-> Cu(OH)2(H2O)4 + 2NH4^+ Cu(OH)2(H2O)4 + 4NH3 —> [Cu(NH3)4(H2O)2]^2+ + 2H2O + 2OH^-In the first reaction, two ammonias react because each one removes a H^+ and you need to remove two H^+ ions to form the neutrally charged hydroxide.