You can put this solution on YOUR website! When does cos (x) = 0? From the "unit circle" cos (x)=0 when In terms of degrees: 90 and 270 degrees In terms of radians: (pi)/2 and 3 (pi)/2 radians

You can put this solution on YOUR website! If tanx=-1/3 ; cosx>0 -- Since tan is negative and cos is positive, x is in the 4th quadrant. -------------- tan = y/x = -1 ...

Question 966031: For sin2x+cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation in the interval [0,2π).

You can put this solution on YOUR website! Solving these problems can be broken down into three stages: Using Trig properties and/or algebra, transform the given equation into one or more equations of the form: TrigFunction (variable-expression) = some-number Find the general solution for the equation (s) from part 1 If the problem asks for solutions in a specific interval, …

Question 838599: \Find the general solution: cosx*tanx -cosx=0 Thanks! Answer by lwsshak3 (11628) (Show Source):

Jul 23, 2011 · As skeeter stated, after squaring both sides you must check the solutions. For example, in the first quadrant, both Sinx and Cosx are non-negative and hence they cannot sum to zero. Cosx is zero at multiples of 90 degrees and Sinx is zero at 0 degrees and multiples of 180 degrees, so they are never zero for the same x. Solutions to Cosx+Sinx=0 require they be …

Mar 20, 2018 · You can use this altered Pythagorean identity: sin2 = 1 −cos2x Now here's the actual problem. The strategy is to get everything in terms of cosx, then factor it like a quadratic. Here's what that looks like: 2sin2x = 1 +cosx 2(1 −cos2x) = 1 + cosx 2 − 2cos2x = 1 +cosx −2cos2x + 2 = 1 + cosx −2cos2x − cosx + 2 = 1 −2cos2x − cosx + 1 = 0 2cos2x + cosx − 1 = 0 …

Question 775657: solve 2sinx+cosx=0 Answer by Tatiana_Stebko (1539) (Show Source):

Mar 12, 2018 · How do you solve cos x sin x = cos x in the interval 0 ≤ x ≤ 2π?

You can put this solution on YOUR website! need to get rid of either the sin or cos... to make an equation in just one "variable". The obvious one is the sin 2x since there is a formula: sin2x = 2sinx cosx so, 2sinXcosX - cosX = 0