Feb 3, 2025 · The line of impact and the net are perpendicular to the horizontal ground. Shot 2 Shot 32 m I Line of impact 50°C 30° Net How much higher is shot 2 than shot 1? Draw a rough diagram and show your work. [CBSE 2024 (Note: Take sin 30° as 0.5, cos 30° as 0.9, sin 50° as 0.8 and cos 50° as 0.6.)

Jul 5, 2019 · Answer: Valur of Cos 50 is 0.64 to be exact. Explanation: If we see calues of cos we see that increasing the angle decrease the value so if cos 60 is 0.5 cos 50 may be approx around 0.6

Sep 23, 2018 · Prove that cos 10 degree cos 30 degree cos 50 degree cos 70 degree is equal to 3 by 16 - 5831151 vivekraj95 vivekraj95 23.09.2018

Feb 14, 2018 · (i) cos 50° sin 40° + sin 50° cos 40° To find: (i) The solution of the given expression. Solution: We know that . cos x° = sin (90°-x°) So, cos 50° = sin (90°-50°) = sin 40° Thus, cos 50° sin 40° = sin 40° sin 40° = sin² 40 ° Again, sin x° = cos (90°-x°) So, sin 50° = cos (90°-50°) = cos 40° Thus,

Dec 1, 2018 · Answer: sin 50° cos 10° + cos 50° sin 10° = Step-by-step explanation: Since we have given that . sin 50° cos 10° + cos 50° sin 10° As we know that . sin A cos B + cos A sin B = sin(A+B) Here, A = 50° and B = 10° So, sin 50° cos 10° + cos 50° sin 10° = sin(50°+10°)= sin 60° and the value of sin 60° =

May 25, 2017 · Given: Cos10°cos50°cos70°=√3/8 To find: Here we have to prove LHS = RHS Solution: Here we will take the LHS First

May 8, 2018 · Click here 👆 to get an answer to your question ️ cos 10 cos 50 cos 70=root 3/8

Oct 11, 2019 · cos 60 cos 10 - sin 10 sin 60 + cos 60 cos 10 + sin 10 sin 60. After cancellation similar terms, we get: 2 sin 60 cos 10 / 2 cos 60 cos 10. Cancelling cos 10 and 2, we get: sin 60 / cos 60 tan 60 = √3. Answer: So the value of sin 70 + sin 50 / cos 70 + cos 50 is √3.

Find an answer to your question prove that cos 10°.cos 50°.cos 60° .cos 70° = ranjitdhunna613 ranjitdhunna613 23.12.2019

Mar 23, 2023 · cos(0) is equal to 1, so we can simplify further: 1 + 2 cos(50) cos(20) + 2 cos(35) cos(15) = 0 This equation cannot be solved algebraically, but it can be solved numerically using a calculator or computer software.