Basically when we % w.p f for output w refers to the minimum number of position to be use for displaying the value and p refers to the number of digit after decimal point. %3.2f floating point …

This means that the calculation will be slower (though more accurate) than it would have been if you had written 2.0f or 2. Had you written 2, the constant would be of int type, which would be …

Historically, the first extensions used for C++ were .c and .h, exactly like for C. This caused practical problems, especially the .c which didn't allow build systems to easily differentiate C++ …

For any f,g: N->R*, if f(n) = O(g(n)) then 2^(f(n) = O(2^g(n)) (1) We can disprove (1) by finding a counter-example. Suppose (1) is true -> by Big-O definition, there exists c>0 and integer m >= …

May 6, 2011 · f,F The double argument is rounded and converted to decimal notation in the style [-]ddd.ddd, where the number of digits after the decimal-point character is equal to the …

Jun 21, 2013 · 0.58 (without the f suffix) is a literal of type double and one cannot assign a double value to a float, just like one cannot assign an int value to a string. However you can assign a …

Sep 16, 2014 · That has to do with the fact that arguments following the ellipse in the function prototype are subject to default argument promotions as per section 6.5.2.2 Function calls, …

Dec 16, 2015 · def fib_gen(n): """generates fib numbers to avoid rounding errors""" fibs=[1,1] for i in xrange(n-2): fibs.append(fibs[i]+fibs[i+1]) return fibs F = fib_gen(50) #just an example. c=1 …

The decimal point and the f have a different purpose so it is not really .f. You have to understand that in C and C++ everything is typed, including literals. 3 is a literal integer. 3. is a literal …

double f = 1.234; printf("%10.2f",f); // 10 positions wide, 2 decimals at most Output: 1.23 <- print only 2 decimal digits ^^^^^ ||||| 0123456789 <- positions Such code is a bit common when you …