
What are the factors of 145? - Socratic
Dec 9, 2016 · 5 and 29 Factors” are the smallest integers that can be combined by multiplication to obtain the original value. They are all therefore “prime numbers”. They are extremely useful in mathematics in simplifying problems by finding least and greatest common denominators. To factor 145 it is useful to note that it ends with a ‘5’, thus, 5 is a very good factor to start with. To …
What is the measure of the supplement of a 35 degree angle?
Dec 30, 2015 · 145˚ Supplementary angles' measures have a sum of 180˚. Call the unknown supplementary angle's measure x. Thus, 35+x=180 Subtract 35 from both sides. x=145 The supplementary angle is 145˚.
Gabriela is washing cars. She charges $15 for a car wash. She paid …
Oct 5, 2015 · I found that she starts to make a profit after the 12^(th) car. We can translate the situation into an algebraic expression where x is the number of washed cars, as: x(15-3)-145>0 to find when she starts to make a profit: So: 12x-145>0 12x>145 x>145/12=12.08~~12 after the 12^(th) car she starts to make a profit: if x=13: 13*12-145=$11
Question #42ee6 - Socratic
May 21, 2014 · Converting 1.00 mol of steam at 145 °C to ice at -50.0 °C involves the loss of 57.71 kJ of energy. There are five heats to consider: q_1 = heat lost on cooling steam from 145 °C to 100 °C. q_2 = heat lost on condensing steam to water at 100 °C. q_3 = heat lost on cooling water from 100 °C to 0°C. q_4 = heat lost on freezing water to ice at 0 °C. q_5 = heat lost on …
What were the three periods that divided the Mesozoic era?
Mar 26, 2016 · The Mesozoic era is divided into the Triassic, Jurassic, and Cretaceous periods. The Mesozoic era is divided into the following periods from oldest to youngest: Triassic Jurassic Cretaceous The Triassic period was the first and oldest period of the Mesozoic era which occurred approximately 251 to 199.6 million years ago. It was known for the emerging diversity …
A solution is prepared by mixing: - Socratic
May 28, 2018 · What is the pH of a solution prepared by mixing 55.0 mL of 0.183 M #KOH# and 70.0 mL of 0.145 M #HC_2H_3O_2#?
How do you find the 9th term of the arithmetic sequence a10
Mar 15, 2018 · a_9 = 105 Given: arithmetic sequence: a_10 = 100; a_20 = 50 An arithmetic sequence has the form: a_n = a_1+d(n-1), where a_1 is the first number in the sequence, n is the number in the sequence and d is the arithmetic difference between consecutive terms: d = a_2 - a_1 = a_3 - a_2 .... a_10 = a_1 +d*(10-1) = 100 a_10 = a_1 +9d = 100 a_20 = a_1 + d*(20-1) …
A building casts a 50-foot shadow Alex is 5 feet tall and ... - Socratic
May 21, 2016 · Use a ratio to compare like quantities to find the building is 41 2/3 ft high and so approximately 42ft. We can solve this using a ratio: "height of building"/"building shadow" = "Alex height"/"Alex shadow" Let's substitute in what we know: H/50=5/6 where H is the height of the building Let's solve for H: H=(5*50)/6 H=250/6=125/3 ft or in other words 41 2/3 ft and …
What is the Fibonacci sequence? - Socratic
Oct 4, 2015 · The Fibonacci sequence is the sequence 0, 1, 1, 2, 3, 5, 8,..., with first terms 0, 1 and each subsequent term formed by adding the previous two terms.
A 50.0 g sample of copper is at 25.0°C. If l 200 I of ... - Socratic
Mar 6, 2018 · 35,4°C i suppose 200 J of energy from the relation: Q= m xx c_p xx Delta T we have (cp= specific heat of copper) Delta T= Q/(m xx c_p) = (200J)/( 50 g xx 0,385 J/(g °C))=10,4°C The final temperature will be 25,0+ 10,4 = 35,4°C