Jan 2, 2017 · -1/3x^-3+C I would begin by rewriting the expression as x^-4. We then have: intx^-4dx. To integrate or take the anti-derivative, we do the opposite of what we would do if we were taking the derivative; instead of bringing down the power and reducing it by 1, we will add one to the power and multiply what is now the integrand by the reciprocal of the power. =>-1/3x^-3 To account for any ...

Jun 16, 2018 · x inRR,x!=-4, y inRR.y!=0 >"let "y=1/(x+4) "the denominator of y cannot be zero as this would make" "y undefined. Equating the denominator to zero and " "solving gives the value that x cannot be" "solve "x+4=0rArrx=-4larrcolor(red)"excluded value" "domain "x inRR,x!=-4 (-oo,-4)uu(-4,oo)larrcolor(blue)"in interval notation" "to find the range, rearrange making x the subject" y(x+4)=1 xy+4y=1 xy ...

Solve the Equation x-4=1 - Answer | Math Problem Solver - Cymath ... \\"Get

Jan 22, 2010 · I am trying to factor x 4 +1 into two multiplied polynomials Homework Equations My teacher gave us this hint that its factored form is (ax2+bx+c)(ax2+bx+c) The Attempt at a Solution First i assumed that a and c were equal to 1 so that when x 2 is multiplied by the other x 2 is gives me x 4 and 1 times 1 gives me 1. I knew that b had to be a ...

Jun 16, 2016 · How do you write the partial fraction decomposition of the rational expression # (3x^2 + 12x

Sep 26, 2016 · Since the denominator is the same as the numerator, you need to do long division first: #(x^4-1)sqrt(x^4)# = #1+1/(x^4-1)#

(x-1) (x-4)>0 - Answer | Math Problem Solver - Cymath ... \\"Get

Apr 8, 2018 · The arc length is 62/5 units. I'm assuming you want us to find the arc length of int_1^x sqrt(t^3 - 1)dt on [1, 4]. Recall that d/dx(int_1^x F(t) dt) = F(x) and that arc length is given by A = int_a^b sqrt(1 + F(x)^2) dx Then we get A = int_1^4 sqrt(1 + (sqrt(x^3 - 1)^2)) dx A = int_1^4 sqrt(x^3) dx A = int_1^4 x^(3/2) dx A = [2/5x^(5/2)]_1^4 A = 2/5(4)^(5/2) - 2/5(1)^(5/2) A = 64/5 - 2/5 = 62 ...

Aug 11, 2015 · {(x = 6), (x=2) :} Start by writing the conditions that a value of x must satisfy in order to be a valid solution to this equation. You have to do that because you're dealing with radical terms, which means that the expressions under the radical signs must be positive for real numbers. 4x+1>=0 implies x >=-1/4 x-2>=0 implies x >= 2 Combine these two conditions to get x>=2. Now go on to solve ...

Dec 21, 2015 · -4/x^2 Use the rule that d/dx[x^n]=nx^(n-1). Also, recall that 4/x=4x^-1. Thus, d/dx[4x^-1]=(4)(-1)x^(-1-1)=-4x^-2=color(blue)(-4/x^2