
How do you simplify the expression #1-(sec^2x-tan^2x)#? - Socratic
Dec 1, 2016 · 0 1-(sec^2x-tan^2x) " " =1-((1/cosx)^2-(sinx/cosx)^2) " " =1-(1/cos^2 x-sin^2 x/cos^2 x) " " =1-((1-sin^2 x)/cos^2 x) " " =1-(cos^2 x/cos^2 x) " " =1-1 " " =0
How do you prove 1/sec^2 x + 1/csc^2 x =1? - Socratic
Mar 3, 2018 · Use reciprocal identity to transform 1/csc^2 x and 1/sec^2 x to 1/[1/ (sin^2 x)] and 1/[1/(cos^2 x)] respectively. Reciprocate sin^2 x and 1/(cos^2 x) you will get sin^2x and cos^2 …
Hi could you please help me with 1+cot^2x/sec^2x - Socratic
Apr 20, 2018 · Hi could you please help me with 1+cot^2x/sec^2x ? Trigonometry. 1 Answer Aviv S. Apr 20, 2018 The ...
How do you prove sec(x) + 1 + ((1-tan^2(x)) / (sec(x)-1 ... - Socratic
Jul 10, 2016 · Let's focus on this expression: secx+1 Note that this is equivalent to (secx+1)/1. Multiply the top and bottom by secx-1 (this technique is known as conjugate multiplication): …
How do you determine graphically and analytically whether …
Feb 24, 2018 · 3) #color(white)(88)color(red)bb(tan^2x=sin^2x/cos^2x)# #y_1=y_2=>sec^2x-1=tan^2x# LHS. By identity 2. #1/cos^2x-1# Add: #(1-cos^2x)/cos^2x# From identity 1: #1 …
(Cos^2x-1)(tan^2x+1)=1-sec^2x? - Socratic
May 22, 2018 · LHS=(cos^2x-1)(tan^2x+1) =-(1-cos^2x)(tan^2x+1) =-(sin^2x)*(sec^2x) =-(sin^2x)/(cos^2x) =-tan^2x =-(sec^2x-1) =1-sec^2x=RHS
How do you show that sec^2xsin^2x = sec^2x - 1? | Socratic
Jul 20, 2017 · Use sin^2x = 1-cos^2x and sec^2x = 1/cos^2x. Trigonometry . Science Anatomy & Physiology Astronomy ...
How do you simplify #(sec^4x-1)/(sec^4x+sec^2x)#? - Socratic
Jul 14, 2016 · Apply a Pythagorean Identity and a couple factoring techniques to simplify the expression to sin^2x. Recall the important Pythagorean Identity 1+tan^2x=sec^2x. We will be …
How do I prove #sec^2x/(2+tan^2x) = 1/(1+cos^2x)#? - Socratic
Apr 28, 2018 · Using: #cosx=1/secx# #1+tan^2x=sec^2x# START: #sec^2x/(2+tan^2x)=1/(1+cos^2x)# #sec^2x/(2+tan^2x)=1/(1+1/sec^2x)# …
What is the derivative of sec^3(2x)-3sec(2x)? - Socratic
Mar 16, 2018 · #intsec^3(2x)-3sec(2x)dx# Apply sum rule and take the constant out,. #color(red)(1/2intsec^3(2x)dx)-color(blue)(3/2intsec(2x)dx#