Oct 23, 2020 · it doesn't matter whether you put #, 0, or any other digit for that matter; One occurrence means: any arbitrary large number; double value = 123467890; Console.WriteLine(value.ToString("#")); // Prints the full number , and . however, are treated different for double

Jan 29, 2015 · NUMBER(p) This represents a fixed-point number with precision p and scale 0 and is equivalent to NUMBER(p,0). and. Specify a floating-point number using the following form: NUMBER. The absence of precision and scale designators specifies the maximum range and precision for an Oracle number.

May 25, 2015 · For those with my issue above, the answer was to swap out # (hash) for 0 (zero). The # gives you no character when there's no value but the 0 gives you a zero when there's no value! Makes sense and works great: $0.0,,"M" –

Jan 13, 2018 · Assuming the assignment is to exclude all strings that consist entirely of zero's, at most one decimal point and possibly leading and/or trailing spaces, here is one way to do it, which requires only standard string functions (and therefore should be faster than any regular-expression solution).

Dec 3, 2008 · width = 10 x = 5 print "%0*d" % (width, x) > 0000000005 See the print documentation for all the exciting details!

Oct 1, 2011 · So string zero "0" is converted to Number data type and boolean false is converted to Number 0. So "0" == false // true. Same applies to ` false == "0" //true === Strict equality check evaluates the arguments with the original data type "0" === false // false, because "0" is a string and false is boolean. Same applies to . false === "0 ...

.wav files cannot be bigger than 4GB as the wave file format specification prevents that. As explained on Wikipedia:

You can set the precision and rounding in its context class, but by default it will retain the number of zeros you place into it: >>> import decimal >>> x = decimal.Decimal('2.0000') >>> x Decimal('2.0000') >>> print x 2.0000 >>> print "{0} is a great number.".format(x) 2.0000 is …

SELECT CAST(CEILING (AVG(CAST(SALARY AS float)) - AVG(CAST(REPLACE(salary, '0', '')AS float) ) ) as int) FROM EMPLOYEES; Here, the actual average salary comes out to be 4046.75 and miscalculated avg salary comes out as 1794.5 Hence the difference 2252.25, which when rounded up is 2253.0, but the hackerrank solution expects it as int, so we need ...

Jul 8, 2013 · So 13 is the closest number to 7 which divides to give remainder 0. Now take the difference (13 ~ 7) = 5 which is the temainder. Note: for this to work divisor should be reduced to its simplest form ex: if 14 is the divisor, 7 has to be chosen to …