If (x + y)/z > 0, is x < 0 ? (1) x < y (2) z < 0 : Data Sufficiency (DS)
Aug 24, 2024 · There are 3 variables (x,y,z) and 1 equation ((x+y)/z>0) in the original condition, and there are 2 more equations given from the 2 conditions, so there is high chance of (C) …
If xyz ≠ 0, is x(y + z) >= 0? : Data Sufficiency (DS) - GMAT Club
4 days ago · I know x(y + z) will always be greater than Zero, combining both options, but mind is saying as x(y + z) can not be equal to zero, in that case should I say x(y + z) is not >= 0 and …
If z ≠ 0 and z + (1 - 2z^2)/z = w/z, then w
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If xyz > 0, is x > 0? (1) xy > 0 (2) xz > 0 : Data Sufficiency (DS)
Jan 31, 2024 · When dividing x(y^2)z>0 with y^2, it becomes yz>0, which is yes and sufficient. Therefore, the answer is C. l For cases where we need 2 more equations, such as original …
What is the general solution of the differential equation # y'''-y ...
Feb 3, 2018 · then as #f(x)# is a polynomial of degree #0#, we would look for a polynomial solution of the same degree, i.e. of the form #y = a# However, such a solution already exists in …
Is yz = x? (1) y > x/z (2) z < 0 : Data Sufficiency (DS) - GMAT Club
(1) y > x/z (2) z < 0 The question asks if yz=x => y=x/z . (1) first statement tells us that y is strictly greater than x/z, that means y not equals x/z. Answer is no . Sufficient. (2) statement 2 says z …
If x < 0, y > 0, and z < 0, which of the following is negative
Since, x<0, y>0, and z<0, the number which is negative should have only one negative number in the product (since multiplying two negatives yields a positive number). Backsolving and …
If x + y + z > 0, is z > 1? (1) z > x + y +1 (2) x + y + 1 < 0 - GMAT …
Apr 6, 2025 · But if x=-0.1,y=-0.1 thus z>0.8 so it may or may not be greater than 1 Not sufficient. A and D ruled out St 2 says x+y+1>0 Again x=-1/2,y=1/2 then z can take any value greater …
If xy + z = x(y + z), which of the following must be true?
2 days ago · I agree with the answer i.e. X=1 OR Z=0 But can the answer be also X=1 AND Z=0 (provided there was an ...
Let z be a random variable with a standard normal ... - Socratic
Mar 8, 2017 · P(-0.86 < Z < 0 ) = 0.2051 The standard convention is to use upper case letters to represent random variables. So P(-0.86 < Z < 0 ) is represented by the shaded area: By …