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Integration by parts: Integral of x sin 2x dx#integrationbyparts #calculus #integral #integrals #integration Note: This integral has been taken from my 100 ...

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= (1/4) (sin2x)- (1/2) (xcos2x)+C. 扩展资料： 求函数f (x)的不定积分，就是要求出f (x)的所有的原函数，由原函数的性质可知，只要求出函数f (x)的一个原函数，再加上任意的常数C就得到函数f (x)的不定积分。 如果F (x)是f (x)在区间I上的一个原函数，那么F (x)+C就是f (x)的不定积分，即∫f (x)dx=F (x)+C。 因而不定积分∫f (x) dx可以表示f (x)的任意一个原函数。

Subtract sin(x) sin (x) from both sides of the equation. Apply the sine double - angle identity. Factor sin(x) sin (x) out of 2sin(x)cos(x)−sin(x) 2 sin (x) cos (x) - sin (x). Tap for more steps... sin(x)(2cos(x)−1) = 0 sin (x) (2 cos (x) - 1) = 0.

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Integrate the function in e x (sinx + cosx). Integrate the function in (x - 3) e x (x - 1) 3. Integrate the function in e 2x sin x. Integrate the function in sin - 1 (2 x 1 + x 2). Evaluate the following. The value of e d ∫ e 5 x (1 x - 1 5 x 2) d x is ______. e dx ∫ e x [x (log x) 2 + 2 log x] dx = ______. ∫ 1 x 2 - a 2 d x = ______.