Jul 17, 2018 · The value of expression #(2(sin1+sin2+...+sin89))/(2(cos1+cos2+...+cos44)+1)=csctheta, theta in (0,pi/2)# then find …

Mar 19, 2018 · To prove that #cos^4x-sin^4x=1-2sin^2x#, we'll need the Pythagorean identity and a variation on the Pythagorean identity:

Feb 6, 2017 · How do you use the power reducing formulas to rewrite the expression #sin^2xcos^2x# in terms of the first power of cosine?

Aug 4, 2018 · #sin 2theta = 120/169, theta in Q_1 and - 120/169, theta in Q_4#. #cos 2theta = 119/169#

Apr 4, 2018 · Using the Pythagorean identity (sin^2theta+cos^2theta=1), the value of sin^2 0+cos^2 0 is 1.

Feb 19, 2018 · #Sin^2θ + 8 sin θ cos θ = cos^2θ # #=>cos^2θ -sin^2theta- 4*2 sin θ cos θ = 0 # #=>cos2θ - 4 sin2 θ= 0 #

May 21, 2016 · (pi/6),(5pi)/6, (3pi)/2 Replace in the equation cos^2 x by (1 - sin^2 x) --> 1 - sin^2 x - sin^2 x - sin x = 0 -2sin^2 x - sin x + 1 = 0 Solve this quadratic equation in sin x. Since a - b + c = 0, use shortcut. The 2 real roots are: sin x = -1 and sin x = -c/a = 1/2. a. sin x = -1 --> x = 3pi/2 b. sin x = 1/2 --> 2 solution arcs --> x = pi/6 x = pi - pi/6 = (5pi)/6 General answers: x = pi/6 ...

Feb 4, 2016 · 1 Without even considering the arguments of sine and cosine, there is an identity that for all x, sin^2(x) + cos^2(x) = 1.

Oct 24, 2017 · What are the units used for the ideal gas law?

May 21, 2016 · Use the Property: #cos(A+B)= cosAcosB-sinAsinB# Left Side: #cos 2x= cos(x+x)=cosx cosx -sinx sinx# #=cos^2x-sin^2x#