
How do you solve sin(2x) - sin(3x) + sin(4x) = 0? - Socratic
May 11, 2015 · The answer is {x in RR : x=kpi or x=(2pi)/3+2kpi or x=-(2pi)/3+2kpi, k in ZZ} Remember: sin(4x)=2sin(2x)cos(2x) sin(3x)=sin(x)cos(2x)+cos(x)sin(2x) sin(2x)(1+2cos(2x))=sin(2x)cos(x)+cos(2x)sin(x) Remember: 1=2-1 sin(2x)(2+2cos(2x)-1-cos(x))=cos(2x)sin(x) Remember: 1+cos(2x)=2cos^2(x) 2sin(x)cos(x)(4cos^2(x)-1 …
How do you find the general solutions for sinx+2tanx=0? - Socratic
Aug 15, 2015 · How do you solve for x in #3sin2x=cos2x# for the interval #0 ≤ x < 2π# See all questions in Solving Trigonometric Equations Impact of this question
How do you solve tan(x/2) - sinx = 0 over the interval 0 to 2pi?
Feb 29, 2016 · 0, pi/4, pi/2, (3pi)/4, (5pi)/4, (3pi)/2, (7pi)/4 and 2pi Call x/2 = t . Apply the identity: sin 2a = 2sin a.cos a (sin t)/(cos t) - 2sin t.cos t = 0.
Suppose tan(θ) is undefined and sin(θ) < 0. Find the exact values …
May 3, 2018 · Suppose tan(θ) is undefined and sin(θ) < 0. Find the exact values of the 6 trigonometric functions of the angle θ?
How do you use a calculator to evaluate #sin(-0.65)#? - Socratic
Apr 1, 2017 · sin x = - 0.65 Calculator gives -> - 0.65 --> 2nd --> sin --> x = - 40^@54 Unit circle gives another x that has the same sin value:
How does acceleration equal g sin theta? - Answers
May 20, 2024 · 0. Log in. Subjects > Science > Physics. How does acceleration equal g sin theta? ... for the constant acceleration of a sphere rolling without slipping on a frictionless inclined plane is given ...
How do you find the general solutions for - Sin(x)=0? | Socratic
Oct 19, 2015 · Given equation: cos^2(x) + sin(x) = 0.....(1) If we can change the cos into sine then we have a quadratic ...
How do you find the value for sin x = 0.723? - Socratic
Oct 18, 2015 · Use calculator. sin x = 0.723 --> arc #x = 46^@30#. Trig unit circle gives another arc x that has the same sin value -->
If sin=0.4, what is sin(-theta) + csc theta? - Socratic
May 26, 2016 · If sin=0.4, what is #sin(-theta) + csc theta#? Trigonometry Right Triangles Relating Trigonometric Functions.
How do you express the complex number in trigonometric form …
May 8, 2015 · I am not sure if I got it right. Your number is in trigonometric form so maybe you want to change it into standard form a+bi...? If is so, you know that: cos0°=1 and sin0°=0 so your complex number becomes: z=2(1+i*0)=2+i0=2 which is a pure Real.