
How do you graph y=2sinpix? - Socratic
Jul 26, 2018 · See graph and details. y = 2 sin pix in 2 [- 1, 1 ] = [ -2, 2 ] Period = ( 2pi )/pi = 2. Amplitude = 2. See graph depicting these aspects.: graph{(y -2 sin (pi x ))(y^2-4)(x^2-1)=0}[-6 6 -3 3] Graph for precisely one half.period, x in [ - 1/2, 1/2 ], using the inverse x-1/pi arcsin(y/2)=0 that does the truncation: graph{x-1/pi arcsin(y/2)=0[-1/2 1/2 -2 2] }
What is the derivative of #2^sin(pi*x)#? - Socratic
Sep 27, 2015 · d/dx2^(sin(pix))=2^(sin(pix))*ln2*cospix*(pi) Using the following standard rules of differentiation: d/dxa^(u(x))=a^u*lna*(du)/dx d/dx sinu(x) = cosu(x)*(du)/dx d ...
How do you evaluate the limit sin((pix)/2) as x approaches 1
Aug 8, 2016 · 1 lim_{x to 1} sin((pix)/2) =sin((pi)/2) Well, sin((pi)/2) = 1 and the function f(t) = sin t is also continuous in t in (oo, oo)
How do you differentiate #2^sin(pi*x)#? - Socratic
Oct 29, 2016 · The derivative is dy/dx=pi*ln2*cos(pix)*2^(sin(pix)) Let y=2^(sin(pix)) Taking the logarithms on both sides lny=ln(2^(sin(pix)))=sin(pix)ln2 So taking the derivatives ...
At what points do the functions y = x^2-x and y = sin pix
Jan 24, 2017 · If #x in (1, 1/2+sqrt(5)/2)# then #sin(pix) < 0# So in each of the intervals #[1/2 - sqrt(5)/2, 0)# , #(0, 1)# and #(1, 1/2+sqrt(5)/2]# the two functions have opposite signs and cannot intersect. So the only two points of intersection are:
How do you find the integral of int (sin(pix))^2*(cos(pix ... - Socratic
Oct 16, 2015 · Add the form int sin^m u cos^n u du with at least one of m, n odd to your mathematical cookbook. int sin^m u cos^n u du with at least one of m, n odd. Integrate by substitution. Do this by pulling off one from the odd power, then convert the remaining even power to the other function. Integrate the resulting polynomial in sinu or cosu term by term. I = int sin^2pixcos^5 pix dx = int sin ...
How do you differentiate #y=2^(sinpix)#? - Socratic
Jul 21, 2017 · dy/dx=piln2cos(pix)2^(sinpix) You must write 2^(sinpix) in an other way : y=2^(sinpix)=e^((sinpix)ln2) Now ...
How do you find the area using the trapezoidal approximation
Feb 26, 2017 · Trapezium rule gives: int_2^5 \ sin(pix) \ dx ~~ 0.629062 The values of f(x)=sin(pix) are tabulated as follows (using Excel) working to 5dp Using the trapezoidal rule ...
How do you find the limit as x approaches 1 of #sin(pix)/(x-1)
Mar 6, 2015 · I would use the de l'Hospital Rule. When your limit gives you #0/0# you can derive the numerator and denominator and then do the limit.
How do you find the intersections points of #y=2cos(2pix
Sep 23, 2016 · How do you find the intersections points of #y=2cos(2pix)# and #y=-2sin(pix)#? Trigonometry Graphing Trigonometric Functions General Sinusoidal Graphs 1 Answer