May 4, 2018 · How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle

Apr 16, 2016 · Trig unit circle and trig table --> #sin ((7pi)/6) = sin (pi/6 + pi) = - sin (pi/6) = - 1/2#

pi/6 The following is a pretty good definition for any inverse function: Let f(x) be a function that has an inverse and let f^-1(x) be that inverse, then f^-1(f(x)) = x and f(f^-1(x)) = x Therefore, the inverse sine "undoes" what the sine does.

Jul 19, 2015 · Find sin (-pi/12) Answer: - 0.259 Call sin (-pi/12) = sin t -> cos 2t = cos (- pi/6) = cos (pi/6) = sqrt3/2 Use trig identity: cos 2t = sqrt3/2 = 1 - 2sin^2 t 2sin^2 t = (2 - sqrt3)/2 sin^2 t = (2 -sqrt3)/4 sin t = sin (-pi/12) = +- sqrt(2 - sqrt3)/2 = +- 0.259. Only the negative answer is accepted: …

Sep 27, 2015 · d/dx2^(sin(pix))=2^(sin(pix))*ln2*cospix*(pi) Using the following standard rules of differentiation: d/dxa^(u(x))=a^u*lna*(du)/dx d/dx sinu(x) = cosu(x)*(du)/dx d ...

Aug 4, 2015 · How do you find the exact values #sin (pi/4)# using the special triangles?

May 25, 2016 · "the value of "sin(pi/3)" " is " "sqrt3/2 "the value of "sin(pi/3)" " is " "sqrt3/2

Jan 14, 2017 · How do you apply the fundamental identities to values of #theta# and show that they are true

Sep 17, 2015 · sin(pi/12) = sqrt(2-sqrt(3))/2 Using the half-angle formula! While we don't know what sin(pi/12) is, we do know what sin(pi/6) is, since the latter is one of the special angles (30º to be precise). We know that sin(x/2) = +-sqrt([1-cos(x)]/2) so we know that sin(pi/12) = sqrt([1-cos(pi/6)]/2) It's positive because it's on the first quadrant. cos(pi/6) = sqrt3/2 if …

Sep 15, 2015 · What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#?