
trigonometry - Does $\sin (5x)=5\sin (x)$? Why or why not ...
No, placing a constant factor inside of the sine function, as in sin(a*x) changes the frequency of the function; if |a| is greater than one, it "squishes" the sine function horizontally, making it oscillate "faster", and if |a| is less than one, it "stretches out" the function horizontally, making it oscillate "slower".
Find $\\sin^5 x + \\cos^5 x$ - Mathematics Stack Exchange
Jul 6, 2021 · Find $\sin^5 x + \cos^5 x$ Ask Question Asked 3 years, 9 months ago. Modified 3 years, 9 months ago.
Find a formula for $\\sin(5x)$ in terms of $\\sin(x)$ and $\\cos(x)$.
$\sin5x=\sin(3x+2x)=\sin3x\cos2x+\cos3x\sin2x=(3\sin x-4\sin^3x)(2\cos^2x-1)+(4\cos^3x-3\cos x)(2\sin x\cos x)$ Now, I think you can take it from here. It is just calculation part you are left with. The formula that were used are: $\sin(a+b)=\sin a\cos b+\cos a\sin b$ $\cos 2x=2\cos^2x-1$ $\sin 2x=2\sin x\cos x$ $\sin 3x=3\sin x-4\sin^3 x$
trigonometry - Trigonometric Idenities for $\sin^5(x)
Sep 23, 2016 · The power reducing formula gets me to $$\int (5/8)\sin X - (5/16)\sin(3X) + (1/16)\sin(5X) $$ and then I can use the multiple angles identity on $\sin(3x)$ and $\sin(5x)$, and then I use the power Identities again on the resultant and I just seem to keep going in circles, unable to get the transformation asked for and answer the question.
Solving $\\sin(5x) = \\sin(x)$ - Mathematics Stack Exchange
Mar 15, 2016 · If I have an equation: $$\sin(5x) = \sin(x)$$ In what case can I equate $$5x = x$$ Is it only when there is a multiply of $2\pi n$ on either side, where n is any integer so $$ 5x = x+2\pi n$$ ...
Integral of $\\sin^5(x)\\cos(x)$ - Mathematics Stack Exchange
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complex numbers - How do I use this fact to find $\sin^5\theta ...
Oct 26, 2018 · $\begingroup$ @JoshuaPeacham $\sin^5 \theta \neq (z-\frac{1}{z})^5.$ It seems likely that you made multiple errors that happened to cancel out. $\endgroup$ – David K Commented Oct 26, 2018 at 17:29
Expansion of $\\sin^5 \\theta$ using the Complex Exponential
How do I expand $\sin^5\theta$ using the complex exponential, in order to obtain: $$\frac{1}{16}\sin 5\theta - \frac{5}{16}\sin 3\theta + \frac{5}{8}\sin\theta$$ Thank you.
algebra precalculus - Find the $\frac mn$ if $T=\sin …
Jan 2, 2019 · Not exactly the most elementary approach, but with complex numbers we could write $$ T = \operatorname{Im}\left(1 + e^{\frac{\pi}{36}i} + e^{2\frac{\pi}{36}i ...
Calculus integration problem: $\int \sin^5 (x) \cos^2 (x)\,dx ...
Oct 21, 2015 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.