This inequality says that the product of x + 5 and x - 2 is positive. If both factors are negative or both are positive, the product is positive. To analyze the signs of each factor, we make a sign graph. First consider the possible values of the factor x + 5 x+5=0 if x=-5 put 0 above -5 on number line x+5>0 if x>-5 put + to the right of -5

Algebra -> Inequalities-> SOLUTION: Sovle each inequality by making a sign graph of the factors. State the solution set in iterval notation and graph it? 5x-x^2<4 Can you please help me sovle this problem? Log On

Algebra -> Customizable Word Problem Solvers -> Age-> SOLUTION: Lisa is 3 years older than Megan.If the product of their age is greater than 4, find; (a)The age of Lisa and Megan ;(b) sign graph; (c) table of x axis.;(d) graph on a number line Log On

How do you determine which part of the graph you have to shade in, when solving systems of linear inequalities? ` Solve the inequality for x or y, whichever is more convenient. ` If you solve for x, and the inequality starts " x > " or "x >", shade the area to the RIGHT side of the line. `

Question 851307: Solve each inequality using the test-point or sign graph method. x^3+7x^2-36 less than/equal to 0 Answer by richwmiller(17219) ( Show Source ):

Question 367168: what does the symbol > with a line under it mean? Found 3 solutions by edjones, Edwin McCravy, tutorcecilia:

Graph of with the boundary (which is the line in red) and the shaded region (in green) ----- Now lets graph the second inequality In order to graph , we need to graph the equation (just replace the inequality sign with an equal sign). So lets graph the line (note: if you need help with graphing, check out this solver) graph of

Now let's graph the equation (replace the inequality sign with an equals sign) Graph of Now plug in a test point (0,0) into the inequality Start with the given inequality. Plug in and Evaluate and simplify. Since the inequality is true, this means that we …

Replace the inequality sign on each inequality with an equals sign. Graph the boundary line. All of your inequalities are geq or leq so use solid boundary lines. After you have graphed each boundary, select a point that is NOT on the boundary. Substitute the coordinate values of the selected point into the original inequality.

2. Graph the equation in a sign graph: x^2+8x-7=0 In question no. 2, I find the roots of it first. Since it's not a perfect square trinomial, and 8 is an even number, I used completing the square. x^2+8x=7 x^2+8x+(8/2)^2=7+(8/2)^2 x^2+8x+16=23 x^2+8x+16-23=0 x^2+8x-7=0 But i ended up returning to the original equation :/ Found 2 solutions by ...