Feb 20, 2018 · sec x/tan x (1/cosx )/(sinx/cosx) 1/cancelcosx xx cancelcosx/sinx 1/sinx = cscx

Mar 8, 2018 · We have: # f(x)=secx # Using the limit definition of the derivative, we have: # f'(x) = lim_(h rarr 0) (f(x+h)-f(x))/h #

Apr 17, 2018 · #(tan^2 x / (sec x + 1)) + 1# #=> ((sec^2 x - 1) / (sec x + 1)) + 1#![https://tinycards.duolingo.com /decks/3xo6pgvJ/trigonometric-identities]()

Oct 29, 2016 · sec x tan x cos x simplifies to tan x. Recall that sec x = 1/(cos x). We will begin by rearranging the factors so that sec x and cos x are beside each other and then proceed with substituting the definition for sec x. sec x tan x cos x tan x sec x cos x tan x (1/(cos x)) cos x tan x ((cos x)/(cos x)) tan x (1) tan x

Jul 27, 2018 · How do you prove #(Sec x/Sin x)-(Sin x/Cos x)=Cot x#? Trigonometry Trigonometric Identities and Equations Proving Identities. 1 Answer

May 10, 2017 · #tan^2(x)=sec^2(x)-1# which is most applicable for this problem. Continuing on, we see that we can substitute #tan^2(x)=sec^2(x)-1# into the problem: #sec(x)(sec^2(x)-1)# #=sec(x)(tan^2(x))# Now, since we know that #sec(x)=1/cos(x)# and #tan(x)=sin(x)/cos(x)#, we can rewrite #sec(x)(tan^2(x))# using only cosines and sines: #1/cos(x)(sin^2(x ...

Jun 14, 2018 · The equation becomes sin(x) = 2(1-sin^2(x)) = 2-2sin^2(x) This is a quadratic equation in sin(x): if we bring everything to left hand side, we have 2sin^2(x)+sin(x)-2 = 0 Let t=sin(x), we have 2t^2+t-2 = 0 If you solve this equation with the quadratic formula, you get t = -1/4 \pm sqrt(17)/4 Since -1/4 - sqrt(17)/4 approx -1.2, it impossible ...

Nov 1, 2015 · f^'(x)=sec^2(x+sec(x))[1+tan(x)sec(x)] When we find functions of functions, the answer is the chain rule, 99% of the times.

Jul 24, 2015 · Simplify: tan x(csc x)/(sec x) Ans: 1 tan x(1/sin x)/(1/cos x) = (sin x/cos x)(1/sin x)(cos x/1) = 1

Sep 24, 2014 · The average rate of change is the slope of the secant line through the points #(0,1)# and #(pi/4,sqrt(2))#. ...