Jul 24, 2015 · Simplify: tan x(csc x)/(sec x) Ans: 1 tan x(1/sin x)/(1/cos x) = (sin x/cos x)(1/sin x)(cos x/1) = 1

We're trying to prove that csc(− x) sec(− x) = − cotx. You'll need to use reciprocal identities: secx = 1 cosx cscx = 1 sinx and also angle difference formulae: sin(x − y) = sinxcosy −cosxsiny cos(x −y) = cosxcosy +sinxsiny Here's the actual problem. I'll be manipulating the right side of the equation until it equals the right:

Mar 3, 2018 · Use reciprocal identity to transform 1/csc^2 x and 1/sec^2 x to 1/ [1/ (sin^2 x)] and 1/ [1/ (cos^2 x)] respectively. Reciprocate sin^2 x and 1/ (cos^2 x) you will get sin^2x and cos^2 x, respectively. sin^2⁡x+cos^2⁡x is equal to 1 by the Pythagorean Fundamental Identity.

Call x the trig angle --> tanx = − 3 5 = − 0.6 --> x = − 30∘96 sin (-30.96) = -0.51 cos (-30.96) = 0.86 tan x = -0.6 cotx = 1 0.6 = 1.67 secx = 1 −0.51 = − 1.96 cscx = 1 0.86 = 1.16

May 5, 2016 · Use Properties: cos(A −B) = cosAcosB + sinAsinB sin(A −B) = sinAcosB − cosAsinB Left Side: = sec2x −cot2(π 2 −x) = 1 cos2x − [cos((π 2) − x) sin((π 2 ...

Aug 13, 2015 · sin2A+ cos2A = 1 csc2xsec2x sec2x + csc2x = 1 sin2xcos2x 1 cos2x + 1 sin2x = 1 sin2xcos2x sin2x+cos2x sin2xcos2x = 1

Jun 25, 2016 · sec(θ)csc(θ) −cot(θ) = 1 cosθsinθ − cosθ sinθ = 1 − cos2θ cosθsinθ = sin2θ cosθsinθ = sinθ cosθ = tanθ

Oct 17, 2015 · 0 is a special angle. cot, csc, and sec are actually just the reciprocals of tan, sin, and cos respectively. Solving cot 0: cot0 = 1 tan0 = 1 0 this is undefined Solving csc 0: csc0 = 1 sin0 = 1 0 this is undefined Solving sec 0: sec0 = 1 cos0 = 1 1 = 1

Jul 22, 2015 · Left Hand Side = 2csc2x Recall that : cscx = 1 sinx ⇒ 2csc2x = 2 ⋅ 1 sin2 x = 2 2sinxcosx = 1 sinxcosx = 1 sinx ⋅ 1 cosx = secxcscx As required.

Dec 2, 2016 · The point (0, 6) is located on the Oy axis. The related arc (angle) is t = π 2. sin t = 1 cos t = 0 tan t = inf. cot t = 0 sect = 1 cos = inf. csct = 1 sin = 1