Nov 10, 2015 · 4NH_3+7O_2->4NO_2+6H_2O The number of atoms of each element must be the same on left and right hand side of equation. We may only add balancing numbers in front (ie molecules) in order to achieve this.

Nov 23, 2015 · How would you determine the percent yield for the reaction between 15.8g of NH3 and excess oxygen to produce 21.8g of NO gas and water?

Mar 14, 2018 · "6.1 mol NH"_3" Balanced equation for the combustion of ammonia "4NH"_3("g") + "3O"_2("g")"rarr"2N"_2("g") + "6H"_2"O(g)" Multiply the given mol "O"_2" by the mol ...

Mar 27, 2018 · When 66.8g of (O2) gas is mixed with 27.8g of (NH3) gas and 25.1g of (CH4) gas, 36.4g of (HCN) gas is produced. What is the percent yield of HCN in this reaction? Chemistry

How would you balance the equation for the combustion of octane: C8H18(l)+O2(g)---->CO2(g)+H2O(l)? How do balanced chemical equations relate to the law of conservation of mass? How would you balance the following double replacement equation: LiNo3 + BaCl2 -->? How would you balance the following equation: NH3 + O2-->NO2 +H2O?

Well, we would represent this as R_2stackrel(delta^-)ddotNstackrel(delta^+)H Nitrogen is more electronegative than hydrogen, and the nitrogen polarizes electron density towards itself. And of course nitrogen is the DONOR atom when ammonia acts as a base or as a ligand...

Oct 21, 2017 · "146 L" Start by converting the word equation to a balanced chemical equation. You know that ammonia, "NH"_3, reacts with oxygen gas, "O"_2, to produce nitric oxide, "NO", which is just another name for nitrogen monoxide, and water vapor, so you can write a balanced chemical equation that looks like this: 4"NH"_ (3(g)) + 5"O"_ (2(g)) -> 4"NO"_ ((g)) + 6"H"_ 2"O"_ ((g)) Now, notice that in ...

Jun 28, 2015 · The expected answer is probably D) "NO"_2^-. Both "CO"_2 and "HCN" also exhibit resonance, but they have only one major contributor. "CO"_2 has two major contributors. To determine if resonance is possible, you draw the Lewis structure and then see if you can put the electrons in different locations. A) "CO"_2 The Lewis structure for "CO"_2 is There are two other resonance contributors, but ...

Apr 15, 2015 · The answer is A) HBr. Since all compounds exhibit weak van der Waals interactions, the criterium to go by will be the presence of dipole-dipole interactions. Dipole-dipole interactions take place in polar molecules, i.e. molecules that have a permanent dipole moment. As a result, your compound must be polar and not form hydrogen bonds. So, starting with hydrobromic acid, HBr. The molecule will ...

Well, what does "old Graham's law of effusion" say...? Would it not be the LIGHTER gases....? Graham's law was a comparative, EXPERIMENTAL, rate law...for gases 1 and 2... "Rate 1"/"Rate 2"=sqrt("Molecular mass of Gas 2"/"Molecular mass of Gas 1") And thus the relative rates of EFFUSION (see here) are INVERSELY proportional to the square root of the ratios of the molecular masses of the gases ...