Nov 22, 2019 · The modf function break the argument value into integral and fractional parts, each of which has the same sign as the argument. It stores the integral part as a double in the …

Jun 2, 2014 · Certainly, the use of modf() is the best, more direct way to separate the integer from the fractional part of a floating point number. The only drawback is in case you want the …

Nov 15, 2012 · modf should be a very fast function indeed, so the problem might be that it is still a function (ie, not being inlined). You could try using exactly the same code from the library but …

However, the imprecision is killing me. I'm using my Frac() and InvFrac() functions to draw an anti-aliased line. Using modf I get a perfectly smooth line. With my own method pixels start …

Mar 17, 2021 · 2 The modf functions break the argument value into integral and fractional parts, each of which has the same type and sign as the argument. They store the integral part (in …

May 20, 2019 · double value = 3.4; double fractional = std::modf(value, nullptr); where I don't want/care about the whole part of the number. Yes, I know I could do "3.4 - 3.0" or the like, but …

Oct 8, 2013 · Check out the modf and modff man page to see where you went wrong. Share. Improve this answer. Follow ...

Mar 14, 2012 · The C99 library has a modf function that given the two functions above could be emulated thus: Math.modf = function(n) { return [Math.trunc(n), Math.frac(n)]; } i.e. it returns an …

Aug 8, 2024 · The weird thing is, when ever it tries to utilize SPI functions (Transmit, Receive, and Transmit/Receive), it will always return HAL_SPI_ERROR_MODF. The SPI1 only have …

Mar 21, 2017 · Now for the modf. The modf in the fractpart =, it first checks x. Pretty much scanning it. After it does that, it stores everything before in the decimal point in inpart. After, …