"Logarithming" sounds like some sort of bad competition where you carve wooden logs or something, but everyone somewhat mathematically inclined would most likely understand that you mean "taking the logarithm" with this. On that note; what I always use myself is what you said yourself, namely "taking the logarithm" or "taking the log of".

Jun 30, 2016 · Logarithm - Transferring properties of a Sum to an Integral. Hot Network Questions Stein Coins for Local ...

The logarithm does not. Suppose the power of the numerator and denominator are equal. Then for large values of x the rational function approaches a constant. The logarithm does not. And if the power of the numerator is greater, the rational function grows at …

Jan 16, 2020 · By finding the logarithm I mean not just deriving the formula for it, but rigorous proof that this formula is correct. If $ A $ is a Jordan block of the form $ \lambda I + N $ , where $ N $ is nilpotent and $ I $ is identity matrix, I know that

Problem $\dfrac{\log125}{\log25} = 1.5$ From my understanding, if two logs have the same base in a division, then the constants can simply be divided i.e $125/25 = 5$ to result in ${\log5} = 1.5$...

May 7, 2015 · The power/logarithm notation, seen as operating on numbers, is initially defined on finite cardinalities, i.e. natural numbers. They can be extended in various ways (for example on reals). Here the issue is to extend them to infinite cardinalities, and any extension is a matter of context and consistency.

Jun 9, 2020 · First a note on the logarithmic map, which isn't really a single map at all, but a family of local inverses of the exponential map.

I can't see the page in Google Books, but what you apparently have there is the logarithm of a unit quaternion $\mathbf q$, which has scalar part $\cos(\theta)$ and vector part $\sin(\theta)\vec{n}$ where $\vec{n}$ is a unit vector. Since the logarithm of an arbitrary quaternion $\mathbf q=(s,\;\;v)$ is defined as

Nov 16, 2012 · So I have never actually found a good answer or even a good resource which discusses this so I appeal to experts here at stack exchange because this problem came up again today. What happens to the units of a physical quantity after I take its (natural) logarithm. Suppose I am working with some measured data and the units are Volts.

Sep 1, 2015 · In this post, the poster suspected that the $\\log$ function would eventually flatten out and approach a straight line. We all know this isn't true of course. But then a commenter pointed out this: @