How do you find the limit of (x-pi)/(sinx) as x approaches pi?
May 5, 2018 · How do you find the limit of # (x-pi)/(sinx)# as x approaches pi? Calculus Limits Determining Limits Algebraically. 1 Answer
How do you use continuity to evaluate the limit sin(x+sinx)?
Sep 26, 2015 · See explanation Long version: Sine is continuous so lim_(xrarra)sinx = sina x is continuous so, lim_(xrarra)x = a The sum of continuous functions is continuous, so …
How do you evaluate # (1-tanx) / (sinx - cos x)# as x ... - Socratic
Apr 14, 2016 · #lim_(x->pi/4) (1-tanx)/(sinx-cosx)=(1-tan(pi/4))/(sin(pi/4)-cos(pi/4))=(1-1)/(1/sqrt2 -1/sqrt2)=0/0# So this is one of the indeterminate type and we can use L ...
How do you find #lim_(x->0^+)(x+sinx)^(tanx)# - Socratic
Feb 19, 2018 · The function #f(x)=(x+sinx)^tanx# with #f:(0,oo)->(0,oo)# has the following graphic: graph{y=(x+sinx)^tanx [-0.282, 4.718, -0.34, 2.16]}
What is the limit of # sinx /(x^2 - 4x)# as x approaches 0?
lim_(x->0)sinx/(x^2-4x) = -1/4 You know that sin0 = 0, so you cannot evaluate this limit by replacing x with zero, since that would get you color(red)(cancel(color(black)(lim_(x …
evaluate # lim_(x rarr 0) (sin3x-sinx)/sinx - Socratic
Sep 3, 2017 · We want to evaluate: # L = lim_(x rarr 0) (sin3x-sinx)/sinx # We can manipulate the limit as follows: # L = lim_(x rarr 0) {(sin3x)/sinx-sinx/sinx} #
How do you evaluate the limit #(tanx-sinx)/(xcosx)# as x ... - Socratic
Oct 29, 2016 · 0 (tanx-sinx)/(xcosx)=sinx/x ((1-cosx)/cos^2x) lim_(x->0)(tanx-sinx)/(xcosx)=lim_(x->0)sinx/x lim_(x->0)((1-cosx)/cos^2x)=1 cdot 0/1 = 0
How do you find the limit of # (x+sinx)/(2x-sinx) - Socratic
Jun 1, 2016 · How do you find the limit of # (x+sinx)/(2x-sinx) # as x approaches infinity? Calculus Limits Determining Limits Algebraically. 1 Answer
How do you find the limit of #sinx / x# as x approaches infinity?
Jun 27, 2016 · 0 lim_{x \to oo} sinx / x we know that sin x \in [-1,1], qquad forall x, ie it is a bounded function so we can re-write the limit as sinx * \ lim_{x \to oo} 1 / x = sin x * 0 = 0
How do you determine the limit of - Socratic
Apr 8, 2018 · lim_(x->oo)sinx/x=0 We'll use the Squeeze Theorem, which states that if we have some function f(x), we define new functions h(x), g(x) such that h(x)<=f(x)<=g(x) Then, we'll …