
What is f(6) if f(x) = 4x? - Socratic
Feb 14, 2016 · f(6)=24 For getting f(6) just put x=6 in f(x)=4x i.e. f(6)=4*6=24 Hence f(6)=24. What are the units used for the ideal gas law?
How do you find f^6(0) where f(x)=xe^x? - Socratic
Feb 6, 2017 · How do you find #f^6(0)# where #f(x)=xe^x#? Calculus Power Series Constructing a Taylor Series. 2 Answers
Given f (5) = 10 and f' (5) = 2 what would be a reasonable
Sep 10, 2017 · f(6) ~~ 12 Method 1 If we consider the Taylor Series of f(x) pivoted about a=5 we get: f(x) = f(5) + ( f'(5) ) / ( 1! ) ( x-5 ) + ( f''(5) ) / ( 2! ) ( x-5 )^2 If we use a linear approximation to f(x) and negate all higher terms, we get: f(x) ~~ f(5) + f'(5) ( x-5 ) ..... [A] This approximation should work well for points x that are close to the pivot a=5. In this case is 6 close 5 is probably ...
If f(6)=-3 How do you write a corresponding ordered solution?
(6,-3) in f. Algebra Graphs of Linear Equations and Functions Graphs in the Coordinate Plane
How do you write f(x) = 2x^2+x− 6 in vertex form? - Socratic
Aug 11, 2017 · Given the polynomial equation. #f(x)=2x^2+x-6# Step 1: Factor out the #x^2# coefficient (in this case, #2#) from both the #x^2# and #x# terms:
If #f(x) = -6x - 3#, then how do you find f(2)? - Socratic
f(2)=-15 Substitute 2 instead of x into your function so you get: f(2)=(-6*2)-3=-12- 3=-15
If f(x) = 5x + 20, what is the value of f(6)? - Socratic
Mar 15, 2018 · 50 f(6)=5*6+20=50
Given polynomial f(x)=x^3-10x^2+19x+30 and a factor x-6 how
Jun 9, 2017 · Given polynomial #f(x)=x^3-10x^2+19x+30# and a factor #x-6# how do you find all other factors?
How do you find the inverse of the function: #f(x)= 6+ sqrt
May 9, 2018 · How do you find the inverse of the function: #f(x)= 6+ sqrt(x+7)#? Precalculus Functions Defined and Notation Introduction to Twelve Basic Functions
How do you find the slope of a tangent line to the graph of the ...
Jun 20, 2017 · Compute the first derivative. The slope of the tangent line is equal to the first derivative evaluated at the x coordinate. Given: f(x)= -5/x^3 The derivative and this is easier to do, if we write the function as: f(x)= -5x^-3 f'(x) = 15x^-4 The slope, m, of the tangent line at x = 6 is f'(6) m = 15(6)^-4 m = 5/432