Dec 8, 2015 · $$\Delta G(T,P)=\Delta G^0 (T)+RT\ln(K_\mathrm{eq})$$ At equilibrium you must have $\Delta G(T,P)=0$ So, it helps me to find the trade-off between free energy contribution …

Sep 14, 2015 · Delta G naught prime means that the pH is 7 (physiologic conditions) everything else is the same. The concentration of [H+] now isn't 1 molar because 1 molar concentration …

May 3, 2016 · So, in terms of $\Delta G^0$, we end up with:$$\frac{dG}{d\xi}=\Delta G^0+RT\ln{Q}$$ This equation shows that, on a graph of G versus $\xi$, the right hand side …

Feb 12, 2023 · Delta S has to do with entropy. If delta S is positive, entropy is increasing (ex. liquid to gas) and if delta S is negative, entropy is decreasing(ex. gas to solid). Using these …

Apr 24, 2023 · $\begingroup$ Thanks for the answer! I don't know if I'm getting it right. Basically, if you know that the reaction is taking place under non standard conditions, then to predict …

Feb 27, 2023 · Using the equation delta G = -RTlnK you can first rearrange it to be lnK = delta G/-RT and then raise both sides by e to undo the ln giving you the final equation of K = e^(delta …

Jan 20, 2019 · In the sums you ask about, always calculate products - reactants. The only experimental quantities you have are the concentrations or pressures so it would be possible …

Apr 29, 2018 · $\begingroup$ The main problem in this diagram, I suppose, is the conflation of two very different concepts: changes in the Gibbs free energy of the system (i.e. the difference …

Nov 6, 2013 · Why is $\\Delta G=\\Delta G^o+RT\\ln Q?$ It feels like all online sources were written for introductory Chemistry students! Where do I find a rigorous proof of this identity? …

Apr 14, 2015 · $\Delta G^{\circ} = -RT\ln K$ $\Delta G = \Delta G^{\circ} + RT \ln Q$ The first one allows us to find the Gibbs free energy at the standard state, as was mentioned. However, it …