
What are the six trig function values of -pi/6? | Socratic
Dec 1, 2015 · These are listed below. cos(-pi/6) = sqrt3 /2 sin(-pi/6)= -1/2 tan(-pi/6) = - 1/sqrt3 sec (-pi/6)= 2/sqrt3 cosec(-pi/6)= -2 cot(-pi/6)= -sqrt3
How do you evaluate #cot((11pi)/6)#? - Socratic
Sep 25, 2016 · How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#?
How do you evaluate #cot (pi/2 + 11pi/6) - Socratic
Jul 4, 2016 · It is observed that #(11pi)/6# is just less than #2pi# and all trigonometric ratios get repeated after #2pi#, Hence, we can have
What is the period of y = cot (x- (pi/6)) and how would I ... - Socratic
Apr 25, 2015 · The period is Pi Given an arc AM = x on the trig unit circle, with point B at the top. From the extremity M rotates clockwise an arc MN = Pi/6. Next, prolong the radius ON until it meets the horizontal tangent axis BZ at point P. The measure of segment BP is the value of cot x.
How do you graph #y=2csc[2(x+pi/6)]#? - Socratic
Jun 24, 2018 · As Below. y = 2 csc (2x + pi/3) Standard form of cosecant function is y = A csc(Bx - C) + D A = 2, B = 2, C = -pi/3, D = 0 Amplitude = |A| = "NONE" for cosecant ...
How do you find the average rate of change of f(x)=cot x
Mar 1, 2018 · How do you find the average rate of change of #f(x)=cot x# over the interval [pi/6, pi/2]? Calculus Derivatives Average Rate of Change Over an Interval 1 Answer
How do you evaluate #cot (π/6) sin (π/3)#? - Socratic
Jun 17, 2016 · 3/2 cot theta=1/tan theta sin(pi/3)=sqrt3 /2 tan(pi/6)=1/sqrt3 cot(pi/6)sin(pi/3)=3/2
How do you evaluate tan(pi/2+pi/6) . cot (pi-pi/6) . cos (pi
Aug 13, 2016 · How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#?
How do you graph # y =cot (x-(pi/6) - Socratic
Jul 11, 2015 · Graph y = cot ( x - pi/6) graph{cot (x - pi/6) [-10, 10, -5, 5]} Trigonometry Graphing Trigonometric Functions Graphing Tangent, Cotangent, Secant, and Cosecant
How do you find the exact value of all 6 trigonometric ... - Socratic
Sep 26, 2015 · Construct a right angled triangle with angles pi/6, pi/3, pi/2 and look at the ratios of the lengths of the sides. Consider an equilateral triangle with sides of length 2. It will have angles pi/3, pi/3, pi/3. Bisect it to make two right angled triangles, with sides of length 1, sqrt(3) and 2, since 1^2 + sqrt(3)^2 = 1 + 3 = 4 = 2^2. The smallest angle of one of these right angled …