Jun 7, 2016 · frac{d}{dx}(e^{cosh (2x)})=e^{cosh (2x)}sinh (2x)2 frac{d}{dx}(e^{cosh (2x)}) Applying the chain rule, frac{df(u)}{dx}=frac{df}{du}cdot frac{du}{dx} Let,cosh (2x)=u ...

Jul 24, 2017 · # I = int \ ln tanh(x/2)/cosh^2x \ dx # I will take a very similar approach to that of Truong-Son N. but I will simplify the expression in the integrand via an initial substitution. We can remove the half-angle via a substitution of the form: # u=x/2 => (du)/dx = 1/2 # and #x=2u# So then substituting into the integral, it becomes:

Apr 12, 2017 · How do you differentiate# y=cosh^-1sqrt(x^2+1)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions

Sep 27, 2017 · As #tanh(x/2)=sqrt((coshx-1)/(coshx+1))# = #sqrt(((coshx-1)(coshx+1))/((coshx+1)(coshx+1))# = #sqrt(cosh^2x-1)/(coshx+1)#

Sep 17, 2017 · Mostly not sure what to use for u-substitution. :\ Calculus Techniques of Integration Integration by Substitution. 1 Answer

May 5, 2016 · How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#? How do you prove that #cos 2x(1 + tan 2x) = 1#?

Mar 8, 2018 · 1/4cos2h(x)+C int sinh(x)*cosh(x)*dx =1/2int sin2h(x)*dx =1/4cos2h(x)+C

Apr 2, 2015 · How do you find the derivative of #cosh(ln x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x). 1 Answer

Sep 10, 2016 · See the explanation and the super Socratic graphs, for this complicated FCF y is a hyperbolic cosine value, and so, abs y >=1 and the FCF graph is symmetrical with respect to y-axis.

Jul 13, 2018 · Find derivation of #tanh^-1x#, hence differentiate #y= tanh^-1 ((2x)/(1+x^2))# ? Calculus. 1 Answer