
What is the value of cos pi/2? - Socratic
Nov 29, 2017 · 0 pi in degree form =180 =cos(180/2) =cos(90) =0. How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?
How do I find the value of cos pi/12? - Socratic
Sep 11, 2015 · It is cos(pi/12)=1/4*(sqrt2+sqrt6) It is cos(pi/12)=cos(pi/3-pi/4)=cos(pi/4)cos(pi/3)+sin(pi/4)sin(pi/3)=sqrt2/2*1/2+sqrt2/2*sqrt3/2=1/4*(sqrt2+sqrt2*sqrt3)=1/4(sqrt2 ...
How do you evaluate #cos^-1[cos(-pi/2)]#? - Socratic
Apr 13, 2018 · pi/2 Cosine is an even function, meaning cos(-x)=cosx. So, cos(-pi/2)=cos(pi/2)=0 Then, we really want cos^-1(0) = x -> cos(x)=0 -> x=pi/2 as the domain of the inverse cosine is [-1, 1].
What is cos^2(pi/4)? - Homework.Study.com
What is cos^2(pi/4)? Trigonometric Functions of Special Angles: The trigonometric functions have different values for every angle, so we must remember the values of the trigonometric functions of special angles.
What is the value of #cos((2pi)/3)#? - Socratic
Jul 30, 2016 · #(2pi)/3 "is an angle in the " color(blue)"2nd quadrant where the cos ratio is negatve"# #rArrcos((2pi)/3)=-cos(pi-(2pi)/3)=-cos(pi/3)=-1/2#
How do you express cos pi/3 as a cofunction of a ... - Socratic
Feb 17, 2015 · How do you express #cos pi/3# as a cofunction of a complementary angle? Trigonometry Right Triangles Trigonometric Functions of Any Angle. 1 Answer
How do you find the sum of all solutions of …
Mar 11, 2018 · How do you find the sum of all solutions of #cosxcos(x+pi/3)cos(pi/3-x)=1/4#. if #x# is in #[0, 6pi]#?
What is the value of cos(pi/4)? - Homework.Study.com
What is the value of {eq}\cos \dfrac{\pi}{4} {/eq} ? Exact Values of Trigonometric Functions for Common Special Angles In a unit circle, we can find derived or exact values for special angles and trigonometric functions.
How do you simplify #cos(pi/2 - x) * csc(-x)#? - Socratic
Apr 5, 2018 · cos(pi/2-x)*csc(-x)=-1 for x not a multiple of pi. We know that the angles of a right triangle must sum to pi radians. Since the right angle is pi/2 radians, the other two angles must sum to pi/2 radians. Therefore pi/2 minus the adjacent angle must be the opposite angle.
What is the value of #cos[pi/3-pi/4]#? - Socratic
Jul 29, 2016 · (sqrt2 + sqrt6)/4 Apply the trig identity: cos (a - b) = cos a.cos b + sin a.sin b cos (pi/3 - pi/4) = cos (pi/3).cos (pi/4) + sin (pi/3).sin (pi/4) = Trig table of ...