Dec 1, 2016 · How to convert L to dm3 and ml to cm3 Questions: 1) 10cm3 to Gm? 2) 10L to Gm? 3) 10mL to Gm? 4) 10dm3 to Gm

Sep 3, 2016 · Both the cm^3 and the mL are units of volume. It is a fact that there are 10^3*L in a m^3. How does this help us? 1*mL=1xx10^-3L But 1*cm^3 = (1xx10^-2m)^3 = 1xx10^-6*m^3 = 10^-6*m^3*L^-1xx10^3*Lm^-3 = 10^-3*L = 1*mL as required. Sometimes, especially in English (i.e. UK) texts, you will find the L quoted as 1*dm^3, i.e "deci ="1/10. 1*dm^3 = (1xx10^-1m)^3 …

Jun 2, 2017 · "1.34 g cm"^(-3) The idea here si that the volume of the rock will be equal to the volume of water it displaces when added to the graduated cylinder. The volume of the water goes from "25.0 mL " -> " 36.2 mL" after the rock is added, so you can say that the volume of the rock will be equal to V_"rock" = "36.2 mL" - "25.0 mL" V_"rock" = "11.2 mL" Now, in order to find the …

Dec 19, 2015 · rho = "0.077 g/mL" As you know, density is defined as mass per unit of volume. That means that every time you're asked to find the density of a substance, you have to determine the mass of one unit of volume of that substance. In this case, the volume is given to you in milliliters, "mL", so one unit of volume will be equal to "1 mL".

Dec 29, 2016 · 20*ml Consider the graphic below, which shows utilization of the density calculation:

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May 30, 2014 · When the temperature is lowered to -5.0° C, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen in dm3? Chemistry Gases Charles' Law

Jun 14, 2016 · The density of the object is 0.32g/(cm^3). In order to determine the density, we have to use the following formula: D=M/V D represents density and it will have units of g/(mL) when talking about a liquid or units of g/(cm^3) when talking about a solid. M represents mass and will have units of grams g. V represents volume and it will have units of mL or cm^(3) We know …

Jun 21, 2016 · Well, the gold nugget displaces (225-85)*mL of water, so the difference is its volume. A more interesting question is the value of the nugget (more interesting to me anyway). As a heavy metal, gold is incredibly dense, and has rho=19.3*g*mL^-1; this is almost twice the density of lead. Given that the current price of gold is "$41-39USD"*g^-1 can you tell me the …

Apr 28, 2017 · Then that means you have "0.98 L H"_2"SO"_4 in "1 L" solution, for instance. Let's assume we are at "298.15 K". Then, assuming the density of 98% "v/v" "H"_2"SO"_4 is approximately the same as pure "H"_2"SO"_4, we have: "0.98 L H"_2"SO"_4 xx "1.84 g"/"mL" xx "1000 mL"/"L" ~~ "1803.2 g" and the mols of it would be: "1803.2 g H"_2"SO"_4 xx "1 …