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If you want a way to proceed, we can make use of the Taylor expansion of the arctangent function: \arctan(x) = \sum_{k = 0}^{+\infty} \frac{(-1)^k}{2k+1}\ x^{2k+1} Hence you get: \int e^{2\left(\sum_{k = 0}^{+\infty} \frac{(-1)^k}{2k+1}\ x^{2k+1}\right)}\ \text{d}x ...

Detailed step by step solution for arctan(e) Analytics Cookies allow us to understand how visitors use our Services. They do this by collecting information about the number of visitors to the Services, what pages visitors view on our Services and how long visitors are …

The basic formula for arctan is given as θ = arctan(Perpendicular / Base). The derivative of arctan is d/dx(tan -1 x) = 1/(1+x 2 ). The integral of arctan is ∫tan -1 x dx = x tan -1 x - ½ ln |1+x 2 | + C

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The value of arctan (e^1) is 1.21828…

Combine 1 1+e2x 1 1 + e 2 x and ex e x. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Since the exponent x x approaches ∞ ∞, the quantity ex e x approaches ∞ ∞. e x = ∞. The limit as t t approaches ∞ ∞ is π 2 π 2. The result can be shown in multiple forms. Exact Form: Decimal Form: 1.57079632… 1.57079632 …

Feb 26, 2019 · Let $f(x) = e^x$ and $g(x) = \arctan(x)$. I know the range of the function $\arctan(e^x)$ is equal to the intersection of the ranges of $f(x)$ and $g(x)$ . Since the range of $f(x)$ is $[0, \infty)$ and the range of $g(x)$ is $[\frac{-\pi}{2}, \frac{\pi}{2}]$ , the intersection is $[0, \infty) \cap [\frac{-\pi}{2}, \frac{\pi}{2}]$ or $[0, \frac ...

Find the limit as x approaches infinity of \displaystyle{y}={\arctan{{\left({e}^{{x}}\right)}}} ?