Feb 14, 2016 · pi/3 In sin x, x is multi-valued. The only value in the range [ - pi/2, + pi/2] Is defined as arcsin(sin x). Here, use sin (pi - x ) = sin x to attain that val

Nov 18, 2017 · Undefined. Recall the Definition of arc sin fun : arc sin x=theta, x in [-1,1] iff sintheta=x, theta in [-pi/2,pi/2].

Jul 13, 2017 · Given: y=arcsin(3x) Change to f(x) notation: f(x)=arcsin(3x) Substitute f^-1(x) for every x: f(f^-1(x))=arcsin(3f^-1(x)) The left side becomes x by definition: x=arcsin(3f^-1(x)) Use …

Sep 9, 2015 · First let #u = arcsin(5x)# and #y=u^3#. To solve for #(dy)/(du)# where #y = u^3#, we can use the power rule: #(dy)/(du) = 3u^2# To solve for #(du)/(dx)# where #u = arcsin(5x)#, …

Apr 9, 2016 · If #a = arc sin(3/4), sin a = 3/4 and tan a =3/sqrt7#. If #b = arc cos(1/3), cos b = 1/3 and tan b = 2sqrt2# The given expression is

48^@59; 131^@41 arcsin (3/4) Calculator gives: sin x = 3/4 = 0.75 --> arc x = 48^@59 Unit circle gives another arc x that has the same sin value: x = 180 - 48.59 = 131^@41

Oct 12, 2015 · Find arcsin (-3/4) Ans: -48.59 and - 131.41 Calculator gives --> sin x = -3/4 = -0.75 --> arc x = - 48^@59 and x = (- 180 + 48.59) = -131.41

Mar 6, 2018 · How do you simplify the expression #sin(arcsin(3/5)+arctan(-2))#? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions

Apr 16, 2017 · How do you use inverse trigonometric functions to find the solutions of the equation that are in

Aug 11, 2016 · The reqd. value =(11sqrt5)/25. Let arcsin(3/5)=alpha, &, arctan2=beta; alpha, beta in (-pi/2,pi/2). Hence, by defn., sinalpha=3/5>0 so, alpha in (0,pi/2), and ...