
explain why length of AC is 13cm. calculate length of AD
Dec 14, 2017 · To explain why the length of AC is 13 cm, we can use the Pythagorean theorem, which states that in a right-angled triangle, the sum of the squares of the lengths of the two …
Explain why the length of ac is 13 cm - Brainly.com
Jul 14, 2020 · AC=13cm. AD=13,9cm. Step-by-step explanation: a)Pythagoras' Theorem in ABC, right-angle triangle. AC²=AB²+BC². AC²=144cm²+25cm²=169cm². AC=13cm. b)ACD is right …
ABCD is a rectangle with AB =5 cm and diagonal AC =13 cm Find …
Mar 19, 2023 · ac =13cm. To Find, The perimeter of the rectangle abcd. Solution, abcd is a rectangle. side ab = 5cm. ac = 13cm (diagonal of the rectangle) Using Pythagoras theorem. …
Solved: ABC and ACD are both right-angled triangles. a) Explain …
Click here 👆 to get an answer to your question ️ ABC and ACD are both right-angled triangles. a) Explain why the length of AC is 13 cm. b) Calculate the
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Explain why length of AC is 13cm. calculate length of AD
AC is opposite the right angle, so it is the hypotenuse. Use the Pythagorean theorem. (AB)^2 + (BC)^2 = (AC)^2 (12 cm)^2 + (5 cm)^2 = (AC)^2 144 cm^2 + 25 cm^2 = (AC)^2 (AC)^2 = 169 …
Solve AC=13cm.AE=10cm.AD=16 | Microsoft Math Solver
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Solved: Explain why the length of AC is 13 cm. 13cm b ... - Gauth
Explain why the length of AC is 13 cm. 13cm b) Calculate the length of AD. Give your answer correct to 1 decimal place.
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In an isosceles triangle ABC, if AB = AC = 13 cm and the ... - Brainly
Oct 18, 2018 · AB = AC = 13 cm and altitude AD = 5 cm. To Find :-BC. Solution :-In ∆ADB, By applying Pythagoras theorem , we get. AB² = AD² + BD² ⇒ 13² = 5² + BD² ⇒ 169 = 25 + BD² ⇒ …
ΔAbc is an Isosceles Triangle with Ab = Ac = 13cm. the Length of ...
ΔABC is an isosceles triangle with AB = AC = 13cm. The length of altitude from A on BC is 5cm. Find BC. It is given that Δ ABC is an isosceles triangle. Suppose the altitude from A on BC …
∆ABC is an isosceles triangle with AB = AC = 13 cm. The length …
Apr 18, 2020 · Find the length of altitude AD of an isosceles ∆ABC in which AB = AC = 2a units and BC = a units.
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