
SOLUTION: If (2x – 2)(2 – x) = 0, what are all the possible values of …
If (2x – 2)(2 – x) = 0, then 2x-2=0 or 2-x=0. Solve for x in each equation to get x=1 or x=2 So the answer is D) If you need more help, email me at [email protected] Also, feel …
SOLUTION: The problem: Solve the equation. x^2(2x)-2^x=0 This …
If so, you might want to graph y=2x^3 -2^x, and determine where this graph crosses the x axis. The answers I got are x=1 and x=11.61301 approximately!! Maybe you should post this one …
Find the minimum and maximum of P = 5x + 4y subject to
−2x + y >= 2 x = 0 y = 0 the graph looks like this. the area of the graph that is not shaded is your region of feasibility. the corner points of that region are where the maximum / minimum value …
SOLUTION: Please help me solve this equation: {{{2^x=0.125}}}
(2) or (3) x = ln(0.125)/ln(2) Use your scientific calculator to get (4) x = -3 Check your answer with (1).
For any real number x, x2 ≥ x. - Algebra Homework Help
1/4 ≥ 1/2 The last example shows that when x = 1/2, the conjecture x^2 ≥ x is false because 1/4 is not greater than or equal to 1/2. This is what we would call a counterexample, and since we …
x^2 + 3xy + 2y^2 = 1 - 12x + 5y. - Algebra Homework Help
Question 1209900: Let $x$ and $y$ be real numbers such that x^2 + 3xy + 2y^2 = 1 - 12x + 5y. Find all possible values of x + y.
(2 sin2 x − 1)(tan2 x − 3) = 0 - Algebra Homework Help
SOLUTION: Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.) (2 sin2 x − 1)(tan2 x − 3
(b)how high is the ball when it is punted ?(find y when x=0)
Question 1058616: height y (in feet) of punted football is approximated by y = -16/2025 x^2 +9/5x + 5/2 where x is horizontal distance (in feet ) from point at which the ball is punted . (a)use a …
SOLUTION: The following quadratic equation has integer …
Question 853456: The following quadratic equation has integer solutions. x 2 + x − 12 = 0. What is the positive solution of the equation?
SOLUTION: Let x and y be nonnegative real numbers. If x^2
y^2 = 6 - 0.2x^2 y = sqrt(6 - 0.2x^2) Since y is nonnegative, we ignore the negative branch. The expression x+y turns into x + sqrt(6 - 0.2x^2) If you were to graph this, and use the calculator's …