Mar 23, 2018 · Point P_1 At point P_1 the magnetic field due to the wire of radius a is directed to the left, and it has a magnitude of {mu_0 2I}/{2 pi r} = mu_0/pi I/r The point P_1 is at distances of r-a/2 and r+a/2 from the centers of the two smaller wires.

Jan 19, 2018 · The formula for surface area is #S = \pi r^2 + \pi rl# where #r# is the radius of the semicircle and #l# is the length of the hut.

Apr 23, 2016 · How do you determine the amount of liquid a paper cone can hold with a 1.5-inch diameter and a

Jun 6, 2018 · Option: C A(r) = pi r^2, qquad dA(r) = 2 pi r \\ dr By definition of the PDF mathbb P(r): mathbb P(r) * dr = P(r lt X lt r + dr) = (dA)/(pi * 1^2) = 2 r dr implies mathbb P(r) = 2 r Check: int_0^1 mathbb P \\ dr = 1 Expected value of r: langle r rangle = int_0^1 \\ r \\ mathbb P \\ dr = 2 int_0^1 r^2 \\ dr = 2/3

Oct 1, 2015 · We first find the radius from P=2pir, also equal to 8pi r=(8pi)/(2pi)=4 Now the area is: A=pir^2=pi*4^2=16pi

Mar 21, 2017 · Circumference of a circle #=2pir# #:.2pir=12pi# given #:.r=(cancel12^color(red)6*cancelpi^color(red)1)/(cancel2^1cancel*pi^color(red)1)#

Apr 13, 2018 · The solid from revolving around the x-axis is greater . R is the area bounded by: y=2x(2-x) and y=0 (x-axis). 2x(2-x)=0, :. x=0 and 2 This is a parabola that opens down and crosses the x-axis at x=0 and 2 If this area is revolved about the x-axis the resulting solid will look like the following figure: If we cut a vertical slice through the solid with a thickness =dx we will …

Dec 12, 2016 · Arc of 27 inches will subtend a central angle of 4.5 radian. The circumference of the circle is 2*pi*r = 2*pi*6=12pi inches, which subtends central angle of 2pi radian. Therefore arc of 27 inches will subtend a central angle of 27/(12cancelpi)*2cancelpi = 27/6 =4.5 radian.[Ans]

Feb 28, 2016 · The rectangular form (x, y) = ( -3 / 2, - 3sqrt3 / 2 ). r = 3, theta = 4pi/3. x = r cos theta and y = r sin theta. cos 4pi/3 = cos ( pi + pi/3 = - cos pi/3 sin 4pi/3 = sin ( pi + pi/3 = sin pi/3. .

Jun 20, 2016 · The distance between the two points is approximately 1.18 units. You can find the distance between two points using the Pythagorean theorem c^2 = a^2 + b^2, where c is the distance between the points (this is what you're looking for), a is the distance between the points in the x direction and b is the distance between the points in the y direction. To find the …