Aug 2, 2015 · For every possible real u, |u| = {u if u ≥ 0 −u if u <0 So for any two numbers a and b, |a − b| is either equal to a − b if that difference is positive or it is equal to −(a − b) if the difference a − b is negative. π is less than 11, so 11 −π is already positive and |11 −π| = 11 −π Bonus Example |2 − π| π is greater than 2, so 2 −π is a negative number and the ...

May 16, 2018 · We need to know what a radian is to answer this. An angle with an arc that has the same length as the radius of a circle is called a radian. As the circumference of a circle with radius = 1 har a length of 2π, it follows that π rad = 180° Therefore 10 rad = 180∘ ⋅ 10 π = 572.95779513∘ As there are 60' in 1∘ and 60 ” in 1', we get 0.95779513∘ = 0.95779513 ⋅ 3600 …

Mar 31, 2018 · Periods for Cos, Sin, Csc, and Sec functions: P = 2π B Periods for Tan and Cot: P = π B B stands for horizontal stretch or compression So in this case: For: f (t) = cos10t B is equal to 10 Therefore: P = 2π 10 = π 5

Nov 15, 2016 · hope you can read the notation :) deriv .. put in form 5(cos(πt))2 power rule first gets 10(cos(πt)) chain rule requires that you multiply by the deriv of the inside function. d dt (cos(πt)) = − sin(πt) ⋅ π the last multiply by pi is due to the chain rule applied to ( pi t)

Mar 12, 2016 · x=-9,24" "unit y=-3,83" "unit r=-10" "theta=pi/8 "you can convert Polar form to Cartesian form:" x=r*cos theta y=r*sin theta x=-10*cos (pi/8) y=-10*sin (pi/8) x=-9,24 ...

Apr 27, 2018 · 10 radians is about 6.4 ninety degree angles, which puts it comfortably in the third quadrant. Not clear if this is 10 radians or 10 ^circ. Let's do both. 10^circ is obviously in the first quadrant, no need to belabor that.. 10 radians. A quadrant is 90^circ or \pi/2.

Oct 12, 2016 · The restriction for tan−1x is (− π 2, π 2) but 11π 10 is in quadrant III. Since tangent is positive in quadrant III our answer will be in the positive quadrant from the restriction which is quadrant I. So let's find the reference angle which is 11π 10 − π = π 10. Then since the reference angle equals the angle θ in quadrant one our argument in quadrant one is also π 10. Now …

Aug 13, 2017 · Then, sin (pi//5)+cos (pi//5)=sin (3pi//10)+cos (3pi//10), so the natural logarithm simplifies to 0. Thus: int_ (pi//5)^ (3pi//10)sinx/ (sinx+cosx)dx=pi/20

Oct 5, 2015 · The circumference is 10\pi, the area is 25\pi. You just need to apply the definitions: the circumference is 2\pi*r, where r is the radius. In your case, 2pi*5=10\pi. On the other hand, the area is pi*r^2, in your case pi*25.

Jul 21, 2016 · (19/10)pi. tan^ (-1)tan ( (19pi)/10) is the angle whose tangent is tan ( (19pi)/10) = (19/10)pi. From the definitions of successive operations f f^ (-1) (y)=y and f ...