Dec 1, 2016 · 0 1-(sec^2x-tan^2x) " " =1-((1/cosx)^2-(sinx/cosx)^2) " " =1-(1/cos^2 x-sin^2 x/cos^2 x) " " =1-((1-sin^2 x)/cos^2 x) " " =1-(cos^2 x/cos^2 x) " " =1-1 " " =0

Mar 3, 2018 · Use reciprocal identity to transform 1/csc^2 x and 1/sec^2 x to 1/[1/ (sin^2 x)] and 1/[1/(cos^2 x)] respectively. Reciprocate sin^2 x and 1/(cos^2 x) you will get sin^2x and cos^2 x, respectively. sin^2⁡x+cos^2⁡x is equal to 1 by the Pythagorean Fundamental Identity.

Jul 14, 2016 · Apply a Pythagorean Identity and a couple factoring techniques to simplify the expression to sin^2x. Recall the important Pythagorean Identity 1+tan^2x=sec^2x. We will be needing it for this problem. Let's start with the numerator: sec^4x-1 Note that this can be rewritten as: (sec^2x)^2-(1)^2 This fits the form of a difference of squares, a^2-b^2=(a-b)(a+b), with a=sec^2x and b=1. It factors ...

Apr 20, 2018 · Hi could you please help me with 1+cot^2x/sec^2x ? Trigonometry. 1 Answer Aviv S. Apr 20, 2018 The ...

Jul 20, 2017 · Use sin^2x = 1-cos^2x and sec^2x = 1/cos^2x. Trigonometry . Science Anatomy & Physiology Astronomy ...

May 4, 2018 · How do you prove # (sec^2x-1) / (secx - 1) = secx + sin^2x+cos^2x #? Trigonometry Trigonometric Identities and Equations Fundamental Identities 2 Answers

Mar 16, 2018 · #intsec^3(2x)-3sec(2x)dx# Apply sum rule and take the constant out,. #color(red)(1/2intsec^3(2x)dx)-color(blue)(3/2intsec(2x)dx#

Mar 8, 2018 · How do you prove #cos^2x(1-sec^2x)=-sin^2x#? Trigonometry Trigonometric Identities and Equations Proving Identities. 1 Answer

Sep 23, 2016 · #(tan2x)/(2tanx)-sec^2x/(1-tan^2x)# #=(2tanx)/((2tanx)(1-tan^2x))-sec^2x/(1-tan^2x)# #=1/(1-tan^2x)-sec^2x/(1-tan^2x)#

Feb 14, 2016 · Using the following relation, #-\tan ^2x\=1-\sec ^2x# #int (1+1-sec^2(x))/sec^2(x)dx# Applying sum rule, #int f(x)+- g(x) dx=int f(x)dx +- intg(x) dx#