
How to get gateway address when subnetting? - Stack Overflow
Jan 12, 2017 · A subnet mask of /28 would be 255.255.255.240, not 248, not 248. Having 32 subnets with 8 hosts per subnet is impossible with the given mask. The purpose of the mask is that is shows which bits within a network can and can't change. 240 in binary = 1111 0000. This means the first 4 msb in the last value cannot change AND be in the same network.
How many subnets are possible of a given mask - Stack Overflow
Aug 25, 2021 · I read Cisco docs that I can't have subnet addressing of 182.5.0.0 and of 182.5.255.255 because they are the network address and broadcast address of both the main network: 182.5.H.H and the first subnet network and last subnet network. Then the answer should be: The total number of subnet networks = 2^6 -2 = 62
Given an IP address and subnetmask, how do I calculate the CIDR?
256 - 240 = 16 = 2**4, 32 - 4 = 28. It is not really a C# question. To get a net address from an IP and mask you can apply bytewise and to the IP and mask. You can get bytes from a string using IPAddress.Parse() and IPAddress.GetAddressBytes().
Calculating range of IPs from subnet mask - Stack Overflow
Say, I have a subnet of 255.255.255.242 and I have a known IP within that subnet say 192.168.1.101. Now the way I calculate the range of IPs is this: In the subnet mask, find the first octet that is not a 255. In my example, its the 4th octet, and its 242. So take 256 and subtract 242, which gives us 14.
problem calculating subnet mask - Stack Overflow
Feb 5, 2015 · The network bits are represented by the 1's in the subnet mask, and the host bits are represented by 0's. Performing a bitwise logical AND operation on the IP address with the subnet mask produces the network address. For example, applying the Class C subnet mask to our IP address 216.3.128.12 produces the following network address:
Determine the network and host ID portion of an IP address
Dec 28, 2011 · The octet in the subnet mask containing 224 has three consecutive binary 1s in it: 11100000. Therefore the "network portion" of the whole IP address is: 192.168.32.0. The "host portion" of the ip address is 0.0.1.22. Using your notation, the third octet of ip 192.168.33.22 (mask 255.255.224.0) is: 001|00001.
How to compute gaps between IP subnets? - Stack Overflow
Nov 20, 2017 · Adding 1 to that will carry to the part of the address inside the subnet mask, so we can consider that directly. This gives us the bit string we need, but it doesn't tell us the length n of the corresponding subnet mask. Certainly, n must be at least long enough to include all non-zero digits of the string we've obtained.
Identifying subnet mask of the computer in Delphi
Aug 28, 2012 · 2) Even if physically you only have one network card, ypou also have loopback network - 127.x.x.x subnet. If you have some VPN installed like Hamachi or Comodo - that would give one more network adapter.
java - Conversion from CIDR notation to IP address/subnet mask …
Feb 2, 2015 · This number is subtracted from 32 to get a number of 0 in a subnet mask — those bits are also called host bits. In this example we know that we're dealing with /23 prefix and that it's subnet mask should look like: n represents network (16 bits for class B network), s represents subnet, h represents host. For us network and subnet bits are ...
Calculation of the number of hosts per subnet in Class B network
Oct 5, 2011 · If a class B network on the Internet has a subnet mask of 255.255.248.0, what is the maximum number of hosts per subnet? (A) 1022 (B) 1023 (C) 2046 (D) 2047 Can anybody pls tell me the logic of ho...